For the wave function in Example 2.2, find the expectation value of H, at time t=0 ,the “old fashioned way:

H=Ψ(x,0)H^Ψ(x,0)dx.

Compare the result obtained in Example 2.3. Note: BecauseH is independent of time, there is no loss of generality in usingt=0

Short Answer

Expert verified

The expectation value ofHisrole="math" localid="1655393475453" 52ma2 which is same as Example .

Step by step solution

01

Definition of wave function

A wave function is a function that describes the probability of a particle's quantum state as a function of position, momentum, time or spin. The variable Ψ is widely used to represent wave functions.

02

Finding the value of  H^Ψ(x,0)

The expectation value of Hat the time t=0will be evaluated.

The value ofH^Ψ(x,0) have to be found for the calculation of expectation value of H:

H^Ψ(x,0)=22m2x2[Ax(ax]=A22mx(a2x)=A2m

03

Finding the value of H

The expectation value of H can be calculated as,

H=Ψx,0H^Ψ(x,0)dx=A22m0ax(ax)dx=A22m(ax22x33)|0a=A22m(a22a33)=30a52ma36A==52ma2

Thus, the expectation value of His 52ma2which is same as Example 2.3.

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Most popular questions from this chapter

Imagine a bead of mass m that slides frictionlessly around a circular wire ring of circumference L. (This is just like a free particle, except that Ψ(x+L)=Ψ(x)find the stationary states (with appropriate normalization) and the corresponding allowed energies. Note that there are two independent solutions for each energy En-corresponding to clockwise and counter-clockwise circulation; call themΨn+(x) andΨn-(x) How do you account for this degeneracy, in view of the theorem in Problem 2.45 (why does the theorem fail, in this case)?

Analyze the odd bound state wave functions for the finite square well. Derive the transcendental equation for the allowed energies and solve it graphically. Examine the two limiting cases. Is there always an odd bound state?

a) Show that the wave function of a particle in the infinite square well returns to its original form after a quantum revival time T = 4ma2/π~. That is: Ψ (x, T) = Ψ (x, 0) for any state (not just a stationary state).


(b) What is the classical revival time, for a particle of energy E bouncing back and forth between the walls?


(c) For what energy are the two revival times equal?

A particle in the infinite square well (Equation 2.22) has the initial wave function Ψ (x, 0) = A sin3(πx/a) (0 ≤ x ≤ a). Determine A, find Ψ(x, t), and calculate 〈x〉as a function of time. What is the expectation value of the energy? Hint: sinnθ and cosnθ can be reduced, by repeated application of the
trigonometric sum formulas, to linear combinations of sin(mθ) and cos(mθ), with m = 0, 1, 2, . . ., n.

a) Construct ψ2(x)

b) Sketch ψ0,ψ1andψ2

c) Check the orthogonality ofψ0ψ1ψ2 by explicit integration.

Hint:If you exploit the even-ness and odd-ness of the functions, there is really only one integral left to do.

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