If cupric oxide \((\mathrm{CuO})\) is exposed to reducing atmospheres at elevated temperatures, some of the \(\mathrm{Cu}^{2+}\) ions will become \(\mathrm{Cu}^{+}\) (a) Under these conditions, name one crystalline defect that you would expect to form in order to maintain charge neutrality. (b) How many \(\mathrm{Cu}^{+}\) ions are required for the creation of each defect? (c) How would you express the chemical formula for this nonstoichiometric material?

Short Answer

Expert verified
1. Identify the crystalline defect that forms under these conditions to maintain charge neutrality. - The Schottky defect forms when some Cu²⁺ ions are reduced to Cu⁺ ions, causing vacancies in the O²⁻ (oxygen) ions to maintain charge neutrality. 2. Determine the number of Cu⁺ ions required to create each defect. - There needs to be a vacancy in the O²⁻ ion for every two Cu⁺ ions created in the crystal lattice. 3. Provide an expression for the chemical formula of the resulting nonstoichiometric material. - The chemical formula can be expressed as: \(\mathrm{Cu}_{(1-x)}^{2+}\mathrm{Cu}_{x}^{+}\mathrm{O}_{(1-\frac{x}{2})}^0\) where "x" is the fraction of Cu²⁺ ions that are reduced to Cu⁺ ions in the crystal lattice (0 ≤ x ≤ 1).

Step by step solution

01

Identify the crystalline defect

In a crystal lattice of CuO, the presence of Cu²⁺ ions being reduced to Cu⁺ would cause an excess charge, causing the need for a compensating defect. A common defect that can compensate for this excess charge is the formation of a vacancy in the O²⁻ (oxygen) ions. This is known as a Schottky defect.
02

Determine the number of Cu⁺ ions

To maintain charge neutrality in the crystal, the reduction of one Cu²⁺ ion to Cu⁺ requires the creation of a vacancy in O²⁻ ions, as it helps to neutralize the excess charge. Therefore, there needs to be a vacancy in the O²⁻ ion for every two Cu⁺ ions created in the crystal.
03

Express the chemical formula for nonstoichiometric material

Let's say that "x" is the fraction of Cu²⁺ ions that are reduced to Cu⁺ in the crystal lattice (0 ≤ x ≤ 1). The chemical formula for this nonstoichiometric material can be expressed as: \(\mathrm{Cu}_{(1-x)}^{2+}\mathrm{Cu}_{x}^{+}\mathrm{O}_{(1-\frac{x}{2})}^0\) Here, \(\mathrm{Cu}_{(1-x)}^{2+}\) represents the fraction of Cu²⁺ ions remaining, while \(\mathrm{Cu}_{x}^{+}\) represents the fraction of Cu⁺ ions created. The \(\mathrm{O}_{(1-\frac{x}{2})}^0\) represents the fraction of O²⁻ ions present in the lattice with vacancies (the \("-\frac{x}{2}"\) term indicates vacancies that were created).

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