The fracture strength of glass may be increased by etching away a thin surface layer. It is believed that the etching may alter surface crack geometry (i.e., reduce crack length and increase the tip radius). Compute the ratio of the etched and original cracktip radii for a fourfold increase in fracture strength if half of the crack length is removed.

Short Answer

Expert verified
Answer: The ratio of the etched to original crack tip radii is approximately 2.83.

Step by step solution

01

Write the equation for stress intensity factor

The stress intensity factor (K) can be written as: K = Y * σ * sqrt(π * a) where - K is the stress intensity factor - Y is a dimensionless factor dependent on crack geometry, typically in the range of 1 to 3 - σ is the applied stress (fracture strength) - a is the crack length From the problem, it is given that the fracture strength increased by a factor of 4, and half of the crack length is removed.
02

Set up the equations in terms of ratio

Let K₁ and K₂ represent the stress intensity factors before and after etching, and let a₁ and a₂ represent the original crack length and the etched crack length, respectively. Likewise, let R₁ and R₂ denote the original and etched crack tip radii. Now, K₁ = Y * σ₁ * sqrt(π * a₁) and K₂ = Y * σ₂ * sqrt(π * a₂) Given that σ₂ = 4 * σ₁ and a₂ = 1/2 * a₁, we can substitute these values into the equations: K₁ = Y * σ₁ * sqrt(π * a₁) K₂ = Y * (4 * σ₁) * sqrt(π * (1/2 * a₁)) Since the stress intensity factor is related to crack tip radius as: K₂ = K₁ * (R₁ / R₂), we can rewrite the equations above: Y * σ₁ * sqrt(π * a₁) * (R₁ / R₂) = Y * (4 * σ₁) * sqrt(π * (1/2 * a₁))
03

Solve for the ratio R₁ / R₂

Now we have the equation: Y * σ₁ * sqrt(π * a₁) * (R₁ / R₂) = Y * (4 * σ₁) * sqrt(π * (1/2 * a₁)) Cancelling out the common terms (Y, σ₁, and π) from both sides of the equation: sqrt(a₁) * (R₁ / R₂) = 4 * sqrt(1/2 * a₁) Dividing both sides by sqrt(a₁), we get: R₁ / R₂ = 4 * sqrt((1/2 * a₁) / a₁) R₁ / R₂ = 4 * sqrt(1/2)
04

Compute the ratio R₁ / R₂

Now compute the ratio: R₁ / R₂ = 4 * sqrt(1/2) R₁ / R₂ ≈ 2.83 The ratio of the etched to the original cracktip radii is approximately 2.83.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stress Intensity Factor
Understanding the stress intensity factor (SIF) is crucial when evaluating the fracture strength of materials. In the context of glass, the SIF, denoted as 'K', quantifies how stress is distributed around the tip of a crack and helps in predicting the growth of cracks under various stress conditions.

The formula to calculate the SIF is: \[ K = Y \cdot \sigma \cdot \sqrt{\pi \cdot a} \] Here, 'Y' is the dimensionless shape factor reflecting the geometry of the crack, \( \sigma \) is the stress applied at the point of fracture, and \( a \) is the crack length. When a material like glass is etched, the surface crack geometry changes, as does the SIF. By etching, we aim to increase the fracture strength, and hence reduce the likelihood of crack propagation.

Considering the theoretical fourfold increase in fracture strength in the example, it's crucial to note that two main alterations happen post-etching: a reduction of the crack length and an increase in the crack tip radius. These changes, as shown in the exercise, deeply impact the SIF and thus the material's resistance to fracture. By manipulating the SIF through alterations in the crack properties, engineers can enhance the durability of glass and other brittle materials.
Crack Tip Radius
The crack tip radius plays a pivotal role in the strength of a material. It is the measure of the sharpness of the crack tip — the sharper the tip, the more stress is concentrated, and the easier it can propagate, leading to failure. In contrast, a larger crack tip radius indicates a blunter crack, which distributes the stress over a larger area, decreasing the stress concentration and thus the susceptibility to crack growth.

Mathematically, an inverse relationship exists between the crack tip radius (R) and the stress intensity factor: as the crack tip radius increases, the stress intensity factor decreases. This relationship is central to the concept of fracture mechanics and is leveraged in techniques such as the etching process mentioned in the exercise.

When the surface layer of glass is etched, it doesn't just shorten the crack length; it also increases the crack tip radius. It results in a less sharp crack and hence a stronger glass surface. According to the solution, the etching process achieves a ratio of the etched to the original crack tip radii of approximately 2.83, meaning the radius of the crack tip has become blunter by nearly three times after etching. This mechanical improvement greatly enhances the fracture strength of the glass.
Material Property Enhancement
Material property enhancement refers to the various methods and techniques used to improve the properties of materials, such as strength, ductility, and resistance to wear and tear. For glass, which is often seen as a brittle material, increasing the fracture strength is a significant improvement.

Enhancing material properties often involves altering the microstructure or the surface conditions. In the case of glass, as seen in the exercise, surface etching is applied to modify the surface crack geometry — a process that directly leads to a stronger material by reducing the stress concentration factor at the surface cracks.

Material enhancements can also include thermal treatments, alloying, and the introduction of composite structures. In every case, the goal is the same: to improve the performance and service life of the material in its respective applications. Understanding the principles of fracture mechanics, stress distribution, and how microstructural alterations affect these, is a cornerstone of material science that leads to the creation of safer and more durable materials.

This exercise exhibits a practical application of these principles by showing how a simple process such as etching can significantly increase the strength of a glass piece by altering its crack geometry, demonstrating that even small changes at a microscopic level can have a substantial impact on material properties.

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