Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine \(\left[\mathrm{NH}_{2}-\left(\mathrm{CH}_{2}\right)_{6}-\right.\) \(\left.\mathrm{NH}_{2}\right]\) and adipic acid react with one another with the formation of water as a byproduct. What masses of hexamethylene diamine and adipic acid are necessary to yield \(20 \mathrm{kg}\) of completely linear nylon \(6,6 ?\) (Note: the chemical equation for this reaction is the answer to Concept Check \(15.12 .\) )

Short Answer

Expert verified
Answer: To produce 20 kg of completely linear nylon 6,6, we need approximately 9.51 kg of hexamethylene diamine and 11.97 kg of adipic acid.

Step by step solution

01

Write down the balanced chemical equation for the reaction

The balanced chemical equation for the formation of nylon 6,6 from hexamethylene diamine and adipic acid is: \(\mathrm{NH}_{2}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{NH}_{2} + \mathrm{HOOC}-(\mathrm{CH}_{2})_{4}-\mathrm{COOH} \rightarrow [-\mathrm{NH}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{NH}-\mathrm{CO}-\left(\mathrm{CH}_{2}\right)_{4}-\mathrm{CO}-]_{n} + \mathrm{H}_{2}\mathrm{O}\) Here, \(n\) represents the number of repeating units in the nylon 6,6 chain.
02

Calculate the molecular weights of the reactants and product

We need to find the molecular weights of hexamethylene diamine, adipic acid, and the repeating unit in nylon 6,6: - Molecular weight of hexamethylene diamine: \(\mathrm{NH}_{2}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{NH}_{2}\) - (2 x 14) + (12 x 6) + (16) = 116 g/mol - Molecular weight of adipic acid: \(\mathrm{HOOC}-(\mathrm{CH}_{2})_{4}-\mathrm{COOH}\) - (12 x 6) + (16 x 2) + (16 x 2) + 2 = 146 g/mol - Molecular weight of the repeating unit of nylon 6,6 (excluding water): \([-\mathrm{NH}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{NH}-\mathrm{CO}-\left(\mathrm{CH}_{2}\right)_{4}-\mathrm{CO}-]\) - 116 + 146 - 18 = 244 g/mol
03

Determine the amount of each reactant needed for 20 kg nylon 6,6

First, we'll convert 20 kg of nylon 6,6 into moles, using the molecular weight of the repeating unit: \(20,000 \thinspace\mathrm{g} \cdot \frac{1 \thinspace\mathrm{mol}}{244 \thinspace\mathrm{g}} = 81.97\) moles (approximately) Now, using the stoichiometry from the balanced equation (1:1 ratio), we can calculate the amount of each reactant needed in grams: Amount of hexamethylene diamine needed: \(81.97 \thinspace\mathrm{moles} \cdot \frac{116\thinspace\mathrm{g}}{1 \thinspace\mathrm{mol}} = 9508.32\) grams Amount of adipic acid needed: \(81.97 \thinspace\mathrm{moles} \cdot \frac{146\thinspace\mathrm{g}}{1 \thinspace\mathrm{mol}} = 11967.02\) grams
04

Provide the final answer

To yield 20 kg of completely linear nylon 6,6, we need 9508.32 grams (approximately 9.51 kg) of hexamethylene diamine and 11967.02 grams (approximately 11.97 kg) of adipic acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Condensation Polymerization
When we explore the creation of materials like Nylon 6,6, we delve into the fascinating world of condensation polymerization, a chemical reaction where monomers link together, losing small molecules as byproducts, often water. This particular polymerization is like constructing a train by joining carriages end-to-end, each time releasing a puff of steam. In the Nylon 6,6 synthesis, hexamethylene diamine and adipic acid are the 'carriages' forming a polymer chain and releasing water.

The beauty of this process is that it's methodical, linking one monomer unit after another, building up a large molecule, or polymer, that has repeating structural units. To envision this, imagine a zipper where each monomer is a tooth, and as it pulls together, something small separates, signifying the condensation aspect of the reaction.
Stoichiometry
The term stoichiometry is derived from the Greek words for 'element' and 'measure,' and it's a way to quantify relationships within a chemical reaction. It operates on the principle of conservation of mass where the mass of the reactants equals the mass of the products. To relate this to a kitchen recipe, think about how many eggs and how much flour you'd need to make a cake – that’s stoichiometry in action.

In our Nylon 6,6 example, we treated stoichiometry as our recipe book, letting us calculate the exact amounts of hexamethylene diamine and adipic acid required to produce a specific mass of nylon. Since the chemical equation is balanced with a 1:1 molar ratio, it operates like a precise cooking recipe ensuring we use each ingredient in just the right amount to get our desired product.
Molecular Weight Calculation
When we measure out our ingredients in chemistry, we're not using cups and teaspoons, but rather a scale called molecular weight, which essentially tells us the 'weight' of a formula unit of a substance. Seeing molecular weight as a bridge, it allows us to convert between the mass of a substance and the number of moles, which represents the count of molecules.

Calculating the molecular weight is akin to tallying up the weight of each atom in a molecule, based on the atomic weights found on the periodic table. For the Nylon 6,6 synthesis, we calculated the molecular weight of each reactant and the polymer to determine how many grams of each reactant are needed to result in a targeted mass of the final polymer. It's a lot like calculating how much of each type of fruit you need to get a pound of fruit salad.

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Most popular questions from this chapter

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