(a) Write an expression for the modulus of elasticity for a hybrid composite in which all fibers of both types are oriented in the same direction. (b) Using this expression, compute the longitudinal modulus of elasticity of a hybrid composite consisting of aramid and glass fibers in volume fractions of 0.25 and 0.35 respectively, within a polyester resin matrix \(\left[E_{m}=4.0 \mathrm{GPa}\left(6 \times 10^{5} \mathrm{psi}\right)\right]\)

Short Answer

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Question: Determine the longitudinal modulus of elasticity of a hybrid composite made of aramid and glass fibers within a polyester resin matrix, with given volume fractions and properties. Answer: The longitudinal modulus of elasticity of the hybrid composite is 44.65 GPa.

Step by step solution

01

Derive the expression using the Rule of Mixtures

The Rule of Mixtures for anisotropic materials states that the modulus of elasticity of the composite (E_c) can be calculated by summing the product of each constituent's modulus of elasticity (E_i) and its volume fraction (V_i): \(E_c = \sum_i E_i V_i\) In this case, we have two types of fibers embedded in a matrix. We can consider the matrix as a third component in the composite. Therefore, the expression for the modulus of elasticity of a hybrid composite becomes: \(E_c = E_{f1} V_{f1} + E_{f2} V_{f2} + E_{m} V_{m}\) Where: \(E_c\) = Modulus of elasticity of the hybrid composite; \(E_{f1}\) = Modulus of elasticity of fiber type 1; \(E_{f2}\) = Modulus of elasticity of fiber type 2; \(E_m\) = Modulus of elasticity of the matrix; \(V_{f1}\) = Volume fraction of fiber type 1; \(V_{f2}\) = Volume fraction of fiber type 2; \(V_m\) = Volume fraction of the matrix. (Note: \(V_{f1} + V_{f2} + V_{m} = 1\)) #b) Calculate the longitudinal modulus of elasticity#
02

Identify the given information

We are given the following information about the composite material: 1) Volume fraction of aramid fibers: \(V_{f1} = 0.25\); 2) Volume fraction of glass fibers: \(V_{f2} = 0.35\); 3) Volume fraction of the polyester resin matrix: \(V_m = 1 - (V_{f1} + V_{f2})\); 4) Modulus of elasticity of the matrix (in GPa): \(E_m = 4.0 \mathrm{GPa} (6 \times 10^{5} \mathrm{psi})\). In addition, we can look up the modulus of elasticity for the aramid and glass fibers in the literature. Here, we will use the following values: 1) Modulus of elasticity of aramid fibers: \(E_{f1} = 70 \mathrm{GPa}\); 2) Modulus of elasticity of glass fibers: \(E_{f2} = 73 \mathrm{GPa}\).
03

Substitute the values into the expression from part (a)

Now, we can substitute all these values into our derived expression from part (a) to find the longitudinal modulus of elasticity for the hybrid composite: \(E_c = E_{f1} V_{f1} + E_{f2} V_{f2} + E_{m} V_{m}\) \(E_c = 70 \times 0.25 + 73 \times 0.35 + 4.0 \times (1 - (0.25 + 0.35))\)
04

Calculate the longitudinal modulus of elasticity

Now, we can simply calculate the value for \(E_c\): \(E_c = 17.5 + 25.55 + 1.6 = 44.65 \mathrm{GPa}\) Hence, the longitudinal modulus of elasticity of the given hybrid composite consisting of aramid and glass fibers within a polyester resin matrix is 44.65 GPa.

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Most popular questions from this chapter

(a) Cite several reasons why fiberglassreinforced composites are utilized extensively. (b) Cite several limitations of this type of composite.

Compute the longitudinal tensile strength of an aligned glass fiber-epoxy matrix composite in which the average fiber diameter and length are \(0.015 \mathrm{mm}\left(5.9 \times 10^{-4} \mathrm{in.}\right)\) and \(2.0 \mathrm{mm}(0.08\) in.), respectively, and the volume fraction of fibers is 0.25 . Assume that (1) the fiber-matrix bond strength is \(100 \mathrm{MPa}(14,500 \mathrm{psi}),(2)\) the fracture strength of the fibers is \(3500 \mathrm{MPa}\left(5 \times 10^{5} \mathrm{psi}\right)\), and (3) the matrix stress at composite failure is \(5.5 \mathrm{MPa}(800 \mathrm{psi})\).

Compute the longitudinal strength of an aligned carbon fiber-epoxy matrix composite having a 0.20 volume fraction of fibers, assuming the following: (1) an average fiber diameter of \(6 \times 10^{-3} \mathrm{mm}\left(2.4 \times 10^{-4} \mathrm{in.}\right)\) (2) an average fiber length of \(8.0 \mathrm{mm}(0.31 \text { in. })\) (3) a fiber fracture strength of \(4.5 \mathrm{GPa}\) \(\left(6.5 \times 10^{5} \mathrm{psi}\right),(4)\) a fiber-matrix bond strength of \(75 \mathrm{MPa}(10,900 \mathrm{psi}),(5)\) a matrix stressat composite failure of \(6.0 \mathrm{MPa}(870 \mathrm{psi})\) and (6) a matrix tensile strength of \(60 \mathrm{MP}\) \((8,700 \mathrm{psi})\)

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(a) For a fiber-reinforced composite, the efficiency of reinforcement \(\eta\) is dependent on fiber length \(l\) according to $$\eta=\frac{l-2 x}{l}$$ where \(x\) represents the length of the fiber at each end that does not contribute to the load transfer. Make a plot of \(\eta\) versus \(l\) to \(l=50\) \(\mathrm{mm}(2.0 \text { in. })\) assuming that \(x=1.25 \mathrm{mm}\) \((0.05 \text { in. })\) (b) What length is required for a 0.90 efficiency of reinforcement?

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