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Chapter 4: Problem 10

What is the composition, in atom percent, of an alloy that contains 33 g copper and 47 g zinc?

Short Answer

Expert verified
Answer: The composition of the Cu-Zn alloy in atom percent is approximately 41.94% copper and 58.06% zinc.

Step by step solution

01

1. Determine the number of moles of copper and zinc in the alloy

To find the number of moles, divide the given masses by the molar mass of each element. The molar mass of copper (Cu) is 63.5 g/mol and the molar mass of zinc (Zn) is 65.4 g/mol. Number of moles of copper = \(\frac{33g}{63.5\frac{g}{mol}} \approx 0.52\, mol\) Number of moles of zinc = \(\frac{47g}{65.4\frac{g}{mol}} \approx 0.72\, mol\)
02

2. Find the total moles of atoms in the alloy

Add together the moles of copper and zinc to compute the total moles of atoms in the alloy. Total moles of atoms = Moles of copper + Moles of zinc = 0.52 mol + 0.72 mol = 1.24 mol
03

3. Calculate the atom percent of each element in the alloy

To find the atom percent of each element in the alloy, divide the number of moles of that element by the total number of moles, and multiply by 100%. Atom percent of copper = \(\frac{0.52\, mol}{1.24\, mol} \times 100\% \approx 41.94\%\) Atom percent of zinc = \(\frac{0.72\, mol}{1.24\, mol} \times 100\% \approx 58.06\%\)
04

4. Write the final answer

The composition of the Cu-Zn alloy in atom percent is approximately 41.94% copper and 58.06% zinc.

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