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Chapter 4: Problem 7

What is the composition, in atom percent, of an alloy that consists of 92.5 wt\% Ag and \(7.5 \mathrm{wt} \% \mathrm{Cu} ?\)

Short Answer

Expert verified
Answer: The composition of the alloy in atom percent is 87.9% Ag and 12.1% Cu.

Step by step solution

01

1. Calculate moles of Ag and Cu using weight percentages and atomic weights

First, we need to convert the weight percentages to moles. Let's assume we have 100g of the alloy, this means 92.5g of Ag and 7.5g of Cu. We can use the atomic weights of Ag and Cu to find the moles of each element in the alloy. The atomic weight of Ag is 107.87 g/mol, and the atomic weight of Cu is 63.55 g/mol. Moles of Ag = (92.5 g Ag) / (107.87 g/mol Ag) = 0.857 moles Ag Moles of Cu = (7.5 g Cu) / (63.55 g/mol Cu) = 0.118 moles Cu
02

2. Calculate total moles in the alloy

Now, we can add the moles of Ag and Cu to find the total moles in the alloy: Total moles = Moles of Ag + Moles of Cu = 0.857 moles Ag + 0.118 moles Cu = 0.975 moles
03

3. Determine atom percent of each element

To find the atom percent, we'll need to find the fraction of each element's atoms in the total number of atoms: Atom percent of Ag = (moles of Ag / total moles) * 100 = (0.857 / 0.975) * 100 = 87.9 % Atom percent of Cu = (moles of Cu / total moles) * 100 = (0.118 / 0.975) * 100 = 12.1 % So, the composition of the alloy in atom percent is 87.9% Ag and 12.1% Cu.

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