A hypothetical AX type of ceramic material is known to have a density of \(2.65 \mathrm{~g} / \mathrm{cm}^{3}\) and a unit cell of cubic symmetry with a cell edge length of \(0.43 \mathrm{~nm}\). The atomic weights of the A and \(X\) elements are \(86.6\) and \(40.3 \mathrm{~g} / \mathrm{mol}\), respectively. On the basis of this information, which of the following crystal structures is (are) possible for this material: rock salt, cesium chloride, or zinc blende? Justify your choice(s).

Short Answer

Expert verified
Answer: Both Rock Salt and Zinc Blende crystal structures are possible for this material, as their theoretical densities are very close to the actual density.

Step by step solution

01

Determine the formula units per unit cell for each crystal structure

For each crystal structure, we will find the number of formula units (Z) per unit cell. - Rock Salt: 4 formula units per unit cell - Cesium Chloride: 1 formula unit per unit cell - Zinc Blende: 4 formula units per unit cell
02

Calculate the molecular weight of the AX compound

To calculate the molecular weight of the AX compound, we will sum the atomic weights of the A and X elements: Molecular weight of AX = Atomic weight of A + Atomic weight of X = \(86.6 + 40.3 = 126.9 \frac{\mathrm{g}}{\mathrm{mol}}\)
03

Calculate the theoretical density for each crystal structure

With the molecular weight of AX and Avogadro's number (6.0221×10^23 1/mol), we can calculate the theoretical density for each crystal structure using the formula: Theoretical density = \(\frac{Z * Molecular Weight * 10^{24}}{ N_a * a^{3}}\) Where: - Z = Number of formula units per unit cell - Molecular Weight = Molecular weight of the AX compound - \(N_a\) = Avogadro's number (\(6.0221 \times 10^{23} \frac{1}{\mathrm{mol}}\)) - a = Unit cell edge length (\(0.43 nm = 4.3 \times 10^{-8} \mathrm{cm}\)) Calculating the theoretical density for each crystal structure: Rock Salt: \(\frac{4 * 126.9 * 10^{24}}{ (6.0221 \times 10^{23}) * (4.3 \times 10^{-8})^3} = 2.585 \frac{\mathrm{g}}{\mathrm{cm^3}}\) Cesium Chloride: \(\frac{1 * 126.9 * 10^{24}}{ (6.0221 \times 10^{23}) * (4.3 \times 10^{-8})^3} = 0.646 \frac{\mathrm{g}}{\mathrm{cm^3}}\) Zinc Blende: \(\frac{4 * 126.9 * 10^{24}}{ (6.0221 \times 10^{23}) * (4.3 \times 10^{-8})^3} = 2.585 \frac{\mathrm{g}}{\mathrm{cm^3}}\) We know the actual density of the material is 2.65 g/cm³. Comparing the calculated theoretical density values with the actual density: - Rock Salt: Differs by approximately 0.065 g/cm³ - Cesium Chloride: Differs by approximately 2.004 g/cm³ - Zinc Blende: Differs by approximately 0.065 g/cm³
04

Determine the possible crystal structure(s)

Based on the comparison of theoretical density values to the actual density of the AX compound, both Rock Salt, and Zinc Blende are possible crystal structures for this material, as their theoretical densities are very close to the actual density. On the other hand, the Cesium Chloride structure has a much lower theoretical density and is not a possible crystal structure for this material.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For each of the following crystal structures, represent the indicated plane in the manner. of Figures \(3.11\) and \(3.12\), showing both anions and cations: (a) (100) plane for the rock salt crystal structure (b) \((110)\) plane for the cesium chloride crystal structure (c) (111) plane for the zinc blende crystal structure (d) (110) plane for the perovskite crystal structure

In terms of bonding, explain why silicate materials have relatively low densities.

Compute the atomic packing factor for the cesium chloride crystal structure in which \(r_{\mathrm{C}} / r_{\mathrm{A}}=0.732\).

A circular specimen of \(\mathrm{MgO}\) is loaded using a three-point bending mode. Compute the minimum possible radius of the specimen without fracture, given that the applied load is \(425 \mathrm{~N}\left(95.5 \mathrm{lb}_{\mathrm{f}}\right)\), the flexural strength is \(105 \mathrm{MPa}(15,000 \mathrm{psi})\), and the separation between load points is \(50 \mathrm{~mm}\) (2.0 in.).

Using the Molecule Definition Utility found in both "Metallic Crystal Structures and Crystallography" and "Ceramic Crystal Structures" modules of \(V M S E\), located on the book's web site [www.wiley.com/ college/callister (Student Companion Site)], generate (and print out) a three-dimensional unit cell for titanium dioxide, \(\mathrm{TiO}_{2}\), given the following: (1) The unit cell is tetragonal with \(a=0.459 \mathrm{~nm}\) and \(c=0.296 \mathrm{~nm},(2)\) oxygen atoms are located at the following point coordinates: \(\begin{array}{llllll}0.356 & 0.356 & 0 & 0.856 & 0.144 & \frac{1}{2} \\\ 0.664 & 0.664 & 0 & 0.144 & 0.856 & \frac{1}{2}\end{array}\) and (3) Ti atoms are located at the following point coordinates: \(\begin{array}{llllll}0 & 0 & 0 & & 1 & 0 & 1 \\ 1 & 0 & 0 & & 0 & 1 & 1 \\\ 0 & 1 & 0 & & 1 & 1 & 1 \\ 0 & 0 & 1 & & \frac{1}{2} & \frac{1}{2} & \frac{1}{2} \\ 1 & 1 & 0 & & & & \end{array}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free