Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 12: Problem 28

Would you expect Frenkel defects for anions to exist in ionic ceramics in relatively large concentrations? Why or why not?

Short Answer

Expert verified
Explain your answer. Answer: No, Frenkel defects for anions are unlikely to exist in ionic ceramics in relatively large concentrations. This is because anions are generally larger in size and less mobile than cations, making them less likely to form Frenkel defects in the lattice structures of ionic ceramics.

Step by step solution

01

Understand Frenkel defects in ionic ceramics

Frenkel defects are a type of point defect in ionic ceramics, where an ion from its correct lattice site is missing and becomes an interstitial ion, residing in the interstitial space of the lattice. This defect leaves behind a vacancy in the lattice site without any overall loss of ions. It usually occurs in ionic compounds with a significant difference in the size of the cations and anions.
02

Analyze the presence of Frenkel defects in anions

To determine if Frenkel defects for anions are likely to exist in ionic ceramics in relatively large concentrations, we need to understand the factors that influence the formation of these defects. In general, Frenkel defects are more common for cations in ionic ceramics due to their relatively smaller size. The smaller size of cations makes them more mobile in the lattice structure, and thus, more likely to form Frenkel defects. On the other hand, anions are usually larger in size and less mobile, making them less likely to form Frenkel defects.
03

Conclusion and explanation

Based on the factors influencing the formation of Frenkel defects, we would not expect Frenkel defects for anions to exist in ionic ceramics in relatively large concentrations. This is primarily due to the larger size and less mobile nature of anions in the lattice structures of ionic ceramics, making it less likely for these defects to form.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For a ceramic compound, what are the two characteristics of the component ions that determine the crystal structure?

In terms of bonding, explain why silicate materials have relatively low densities.

Compute the atomic packing factor for cesium chloride using the ionic radii in Table \(12.3\) and assuming that the ions touch along the cube diagonals.

On the basis of ionic charge and ionic radii given in Table \(12.3,\) predict crystal structures for the following materials: (a) \(\mathrm{CaO},\) (b) \(\mathrm{MnS}\) (c) \(\mathrm{KBr},\) and (d) \(\mathrm{CsBr}\). Justify your selections.

Briefly explain (a) why there may be significant scatter in the fracture strength for some given ceramic material, and (b) why fracture strength increases with decreasing specimen size.
See all solutions

Recommended explanations on Physics Textbooks

Turning Points in Physics

Read Explanation

Particle Model of Matter

Read Explanation

Kinematics Physics

Read Explanation

Classical Mechanics

Read Explanation

Fields in Physics

Read Explanation

Electrostatics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free