The permeability coefficient of a type of small gas molecule in a polymer is dependent on absolute temperature according to the following equation: $$ P_{M}=P_{M_{0}} \exp \left(-\frac{Q_{p}}{R T}\right) $$ where \(P_{M_{0}}\) and \(Q_{p}\) are constants for a given gas-polymer pair. Consider the diffusion of hydrogen through a poly(dimethyl siloxane) (PDMSO) sheet \(20 \mathrm{~mm}\) thick. The hydrogen pressures at the two faces are \(10 \mathrm{kPa}\) and \(1 \mathrm{kPa}\), which are maintained constant. Compute the diffusion flux [in \(\left.\left(\mathrm{cm}^{3} \mathrm{STP}\right) / \mathrm{cm}^{2} \cdot \mathrm{s}\right]\) at \(350 \mathrm{~K}\). For this diffusion system $$ \begin{aligned} P_{M_{0}} &=1.45 \times 10^{-8}\left(\mathrm{~cm}^{3} \mathrm{STP}\right)(\mathrm{cm}) / \mathrm{cm}^{2} \cdot \mathrm{s} \cdot \mathrm{Pa} \\ Q_{p} &=13.7 \mathrm{~kJ} / \mathrm{mol} \end{aligned} $$ Also, assume a condition of steady state diffusion.

Short Answer

Expert verified
Answer: To find the diffusion flux of water through the polystyrene sheet, follow these steps: 1. Compute the permeability coefficient (\(P_M\)) using the given equation and provided information: $$ P_M = 9.0 \times 10^{-5} \exp \left(-\frac{42,300}{(8.314)(350)}\right) $$ 2. Calculate the diffusion flux (\(J\)) using Fick's first law with the permeability coefficient obtained in step 1 and given pressure difference and sheet thickness: $$ J = - P_M \frac{(20 - 1) \times 10^3}{30 \times 10^{-1}} $$ The diffusion flux (\(J\)) will be expressed in cm^3(STP)/cm^2·s.

Step by step solution

01

Compute permeability coefficient

Using the given equation for permeability coefficient: $$ P_M = P_{M_0} \exp \left(-\frac{Q_p}{RT}\right) $$ Where, \(P_{M_0} = 9.0 \times 10^{-5} (\text{cm}^3\text{STP})(\text{cm}) / \text{cm}^2 \cdot \text{s} \cdot \text{Pa}\), \(Q_p = 42,300 \text{ J/mol}\), \(R = 8.314 \text{ J/mol}·\text{K}\) (universal gas constant), and \(T = 350 \text{ K}\) (temperature). Now, calculate \(P_M\): $$ P_M = 9.0 \times 10^{-5} \exp \left(-\frac{42,300}{(8.314)(350)}\right) $$
02

Calculate diffusion flux

We are given that the water vapor pressures at the two faces are 20 kPa and 1 kPa, and the polystyrene sheet is 30 mm thick. Assuming steady-state diffusion, we can calculate the diffusion flux (\(J\)) using Fick's first law: $$ J = - P_M \frac{ΔP}{l} $$ Where \(ΔP = P_1 - P_2 = (20 - 1) \times 10^3 \, \text{Pa}\) (pressure difference between the two faces), \(l = 30 \times 10^{-1} \, \text{cm}\) (thickness of the sheet). Now, substitute the values and calculate \(J\): $$ J = - P_M \frac{(20 - 1) \times 10^3}{30 \times 10^{-1}} $$ Use the value of \(P_M\) obtained in step 1 to find the diffusion flux \(J\).

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Most popular questions from this chapter

The density and associated percent crystallinity for two nylon 6,6 materials are as follows: \begin{tabular}{cc} \hline\(\rho\left(\mathrm{g} / \mathrm{cm}^{3}\right)\) & crystallinity (\%) \\ \hline \(1.188\) & \(67.3\) \\ \(1.152\) & \(43.7\) \\ \hline \end{tabular} (a) Compute the densities of totally crystalline and totally amorphous nylon \(6,6 .\) (b) Determine the density of a specimen having \(55.4 \%\) crystallinity.

The number-average molecular weight of a poly(styrene-butadiene) alternating copolymer is \(1,350,000 \mathrm{~g} / \mathrm{mol}\); determine the average number of styrene and butadiene repeat units per molecule.

Compute repeat unit molecular weights for the following: (a) poly(vinyl chloride), (b) poly(ethylene terephthalate), (c) polycarbonate, and (d) polydimethylsiloxane.

Make comparisons of thermoplastic and thermosetting polymers (a) on the basis of mechanical characteristics upon heating and (b) according to possible molecular structures.

Molecular weight data for some polymer are tabulated here. Compute (a) the number- average molecular weight and (b) the weightaverage molecular weight. (c) If it is known that this material's degree of polymerization is 710 , which one of the polymers listed in Table \(14.3\) is this polymer? Why? \begin{tabular}{rcc} \hline \multicolumn{3}{|c}{ Molecular Weight Range \((g /\) mol \()\)} & \(\boldsymbol{x}_{\boldsymbol{i}}\) & \(\boldsymbol{w}_{\boldsymbol{i}}\) \\ \hline \(15,000-30,000\) & \(0.04\) & \(0.01\) \\ \(30,000-45,000\) & \(0.07\) & \(0.04\) \\ \(45,000-60,000\) & \(0.16\) & \(0.11\) \\ \(60,000-75,000\) & \(0.26\) & \(0.24\) \\ \(75,000-90,000\) & \(0.24\) & \(0.27\) \\ \(90,000-105,000\) & \(0.12\) & \(0.16\) \\ \(105,000-120,000\) & \(0.08\) & \(0.12\) \\ \(120,000-135,000\) & \(0.03\) & \(0.05\) \\ \hline \end{tabular}

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