Ten kilograms of polybutadiene is vulcanized with \(4.8 \mathrm{~kg}\) sulfur. What fraction of the possible crosslink sites is bonded to sulfur crosslinks, assuming that, on the average, \(4.5\) sulfur atoms participate in each crosslink?

Short Answer

Expert verified
Also, assume that 4.5 sulfur atoms participate in each crosslink on average. Answer: Approximately 9.01% of the possible crosslink sites are bonded to sulfur crosslinks in the given polybutadiene sample.

Step by step solution

01

Determine the number of moles of polybutadiene

To determine the number of moles, we will use the formula: moles = mass / molar mass. The molar mass of polybutadiene (C4H6) can be calculated as \((4 \times 12.01) + (6 \times 1.01) = 54.10 \mathrm{~g/mol}\). Thus, the number of moles of polybutadiene is: moles = \(\frac{10,000 \mathrm{~g}}{54.10 \mathrm{~g/mol}} \approx 184.8 \mathrm{~mol}\)
02

Calculate the number of possible crosslink sites

Since each polybutadiene molecule has two double bonds, there are two possible crosslink sites per mole. The total number of possible crosslink sites is: crosslink_sites = \(2 \times 184.8 \mathrm{~mol} = 369.6 \mathrm{~mol}\)
03

Determine the number of moles of sulfur

The moles of sulfur can be calculated as: moles_S = \(\frac{4,800 \mathrm{~g}}{32.07 \mathrm{~g/mol}} \approx 149.7 \mathrm{~mol}\)
04

Calculate the number of sulfur atoms used in crosslinks

Since 4.5 sulfur atoms participate in each crosslink on average, the number of sulfur atoms used in crosslinks can be calculated as: sulfur_crosslinks = \(\frac{149.7 \mathrm{~mol}}{4.5} \approx 33.3 \mathrm{~mol}\)
05

Calculate the fraction of possible crosslink sites bonded to sulfur crosslinks

Finally, we can calculate the fraction of possible crosslink sites bonded to sulfur crosslinks as: fraction_crosslinked = \(\frac{33.3 \mathrm{~mol}}{369.6 \mathrm{~mol}} \approx 0.0901\) Thus, approximately \(9.01\%\) of the possible crosslink sites are bonded to sulfur crosslinks.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Crosslink Sites Calculation
Understanding the calculation of crosslink sites is critical for assessing the strength and flexibility of vulcanized polymers such as polybutadiene. In the vulcanization process, crosslinks are formed between polymer chains through the addition of sulfur, which provides the necessary rigidity and strength to the material.

Let's break down the concept of 'crosslink sites'. A crosslink site is a point on a polymer chain where bonding with another chain or sulfur atom can occur. For polybutadiene, every molecule has two sites where these bonds can be made because each molecule contains two double bonds capable of reaction.

In a given sample, the number of available crosslink sites is directly proportional to the number of moles of the polymer; specifically, it's double the number of moles because of the two reactive sites per molecule. The step-by-step solution presents a clear approach to calculate how many such sites are actually used in forming crosslinks with sulfur atoms for a set mass of polybutadiene.

Example Calculation:

  • Determine the number of moles of polybutadiene.
  • Identify the number of possible crosslink sites per molecule (which is two for polybutadiene).
  • Multiply the number of moles by the number of sites to get the total possible crosslinks.
Determining what fraction of these sites are involved in sulfur crosslinking gives insights into the extent of vulcanization, which in turn affects the material properties of the final product.
Molar Mass Determination
Molar mass is a fundamental concept in chemistry, including polymer chemistry. It represents the mass of one mole of a substance - be it a single molecule like water or a complex polymer chain like polybutadiene. The molar mass is critical for comparing different substances and for converting between mass and moles, which is often necessary for stoichiometric calculations.

To determine the molar mass of polybutadiene, one would sum the molar masses of all the atoms in its repeating unit, which includes carbon and hydrogen in this case. Since a polybutadiene molecule has four carbon atoms and six hydrogen atoms, the calculation involves multiplying the number of each type of atom by its atomic mass and then summing the results.

Steps for Calculating Molar Mass of Polybutadiene:

  • Identify the chemical formula for one repeat unit (C4H6 for polybutadiene).
  • Look up the atomic masses of carbon (12.01 g/mol) and hydrogen (1.01 g/mol).
  • Multiply the atomic mass of each atom by the number of times it appears in the formula and add these values together.
Knowing the molar mass allows for the conversion of masses to moles, which is essential for understanding the amounts of reactants and products in chemical reactions, such as those involved in the vulcanization of polybutadiene.
Stoichiometry in Polymer Chemistry
Stoichiometry in polymer chemistry deals with the quantitative relationships between reactants and products in polymerization reactions, including vulcanization. It involves calculations based on balanced equations to predict the amounts of substances consumed and produced. For vulcanized polybutadiene, understanding stoichiometry is necessary to determine how much sulfur is needed to achieve a certain degree of crosslinking.

The stoichiometric principles allow for the precise calculation of the number of sulfur atoms that participate in forming crosslinks with the available sites on the polybutadiene chains. This is vital for predicting the resulting material's properties and for ensuring that there isn't an excessive or insufficient amount of sulfur, both of which can lead to suboptimal product qualities.

In the exercise provided, stoichiometry is used to:
  • Calculate the number of moles of polybutadiene and sulfur required.
  • Assess the average number of sulfur atoms involved in each crosslink.
  • Find out the total number of crosslinks formed.
  • Determine the fraction of crosslink sites actually used in the vulcanization process.
By mastering stoichiometry, one can optimize the vulcanization process for producing polybutadiene with the desired strength and elasticity, which is crucial in various industrial applications such as tire manufacturing.

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Most popular questions from this chapter

Which of the following would you expect to be elastomers and which thermosetting polymers at room temperature? Justify each choice. (a) Epoxy having a network structure (b) Lightly crosslinked poly(styrenebutadiene) random copolymer that has a glass transition temperature of \(-50^{\circ} \mathrm{C}\) (c) Lightly branched and semicrystalline polytetrafluoroethylene that has a glass transition temperature of \(-100^{\circ} \mathrm{C}\) (d) Heavily crosslinked poly(ethylenepropylene) random copolymer that has a glass transition temperature of \(0^{\circ} \mathrm{C}\) (e) Thermoplastic elastomer that has a glass transition temperature of \(75^{\circ} \mathrm{C}\)

List two important characteristics for polymers that are to be used in fiber applications.

For each of the following pairs of polymers, plot and label schematic stress- strain curves on the same graph [i.e., make separate plots for parts (a), (b), and (c)] (a) Isotactic and linear polypropylene havng a weight-average molecular weight of \(120,000 \mathrm{~g} / \mathrm{mol}\); atactic and linear polypropyene having a weight-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\) (b) Branched poly(vinyl chloride) having a degree of polymerization of 2000 ; heavily crosslinked poly(vinyl chloride) having a degree of polymerization of 2000 (c) Poly(styrene-butadiene) random copolymer having a number-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\) and \(10 \%\) of the available sites crosslinked and tested at \(20^{\circ} \mathrm{C}\); poly(styrene- butadiene) random copolymer having a number-average molecular weight of \(120,000 \mathrm{~g} / \mathrm{mol}\) and \(15 \%\) of the available sites crosslinked and tested at \(-85^{\circ} \mathrm{C}\). Hint: poly(styrene- butadiene) copolymers may exhibit elastomeric behavior.

Briefly explain how each of the following influences the tensile modulus of a semicrystalline polymer and why: (a) Molecular weight (b) Degree of crystallinity (c) Deformation by drawing (d) Annealing of an undeformed material (e) Annealing of a drawn material

Name the following polymer(s) that would be suitable for the fabrication of cups to contain hot coffee: polyethylene, polypropylene, poly(vinyl chloride), PET polyester, and polycarbonate. Why?

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