Chapter 15: Problem 39
Cite the primary differences between addition and condensation polymerization techniques.
Chapter 15: Problem 39
Cite the primary differences between addition and condensation polymerization techniques.
All the tools & learning materials you need for study success - in one app.
Get started for freeFor each of the following pairs of polymers, plot and label schematic specific volumeversus-temperature curves on the same graph [i.e., make separate plots for parts (a), (b), and (c)]. (a) Spherulitic polypropylene, of \(25 \%\) crystallinity, and having a weight- average molecular weight of \(75,000 \mathrm{~g} / \mathrm{mol}\); spherulitic polystyrene, of \(25 \%\) crystallinity, and having a weight-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\) (b) Graft poly(styrene-butadiene) copolymer with \(10 \%\) of available sites crosslinked; random poly(styrene-butadiene) copolymer with \(15 \%\) of available sites crosslinked (c) Polyethylene having a density of \(0.985\) \(\mathrm{g} / \mathrm{cm}^{3}\) and a degree of polymerization of 2500; polyethylene having a density of \(0.915 \mathrm{~g} / \mathrm{cm}^{3}\) and a degree of polymerization of 2000
Which of the following polyethylene thin films would have the better mechanical characteristics: (1) formed by blowing, or (2) formed by extrusion and then rolled? Why?
Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine \(\left[\mathrm{NH}_{2}-\left(\mathrm{CH}_{2}\right)_{6}-\right.\) \(\mathrm{NH}_{2}\) ] and adipic acid react with one another with the formation of water as a by-product. What masses of hexamethylene diamine and adipic acid are necessary to yield \(37.5 \mathrm{~kg}\) of completely linear nylon 6,6 ? (Note: the chemical equation for this reaction is the answer to Concept Check 15.12.)
Cite four factors that determine what fabrication technique is used to form polymeric materials.
For some viscoelastic polymers that are subjected to stress relaxation tests, the stress decays with time according to $$ \sigma(t)=\sigma(0) \exp \left(-\frac{t}{\tau}\right) $$ where \(\sigma(t)\) and \(\sigma(0)\) represent the timedependent and initial (i.e., time \(=0\) ) stresses, respectively, and \(t\) and \(\tau\) denote elapsed time and the relaxation time; \(\tau\) is a timeindependent constant characteristic of the material. A specimen of a viscoelastic polymer whose stress relaxation obeys Equation \(15.10\) was suddenly pulled in tension to a measured strain of \(0.6\); the stress necessary to maintain this constant strain was measured as a function of time. Determine \(E_{r}(10)\) for this material if the initial stress level was \(2.76\) MPa (400 psi), which dropped to \(1.72 \mathrm{MPa}\) (250 psi) after \(60 \mathrm{~s}\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.