The corrosion rate is to be determined for some divalent metal M in a solution containing hydrogen ions. The following corrosion data are known about the metal and solution: \begin{tabular}{rr} \hline \multicolumn{1}{c}{ For Metal \(M\)} & For Hydrogen \\ \hline\(V_{\left(M M^{2}+\right)}=-0.47 \mathrm{~V}\) & \(V_{\left(\mathrm{H}^{+} / H_{2}\right)}=0 \mathrm{~V}\) \\ \(i_{0}=5 \times 10^{-10} \mathrm{~A} / \mathrm{cm}^{2}\) & \(i_{0}=2 \times 0^{-9} \mathrm{~A} / \mathrm{cm}^{2}\) \\ \(\beta=+0.15\) & \(\beta=-0.12\) \\ \hline \end{tabular} (a) Assuming that activation polarization controls both oxidation and reduction reactions, determine the rate of corrosion of metal \(\mathrm{M}\left(\mathrm{in} \mathrm{mol} / \mathrm{cm}^{2} \cdot \mathrm{s}\right)\) (b) Compute the corrosion potential for this reaction.

Short Answer

Expert verified
Answer: The corrosion rate for metal M is approximately $$5.19 \times 10^{-15}\ \text{mol/cm}^2\text{s}$$, and the corrosion potential for this reaction is 3.5 V relative to the hydrogen standard electrode.

Step by step solution

01

Determine the reaction equation and both half-cell reactions

First, let's determine the overall corrosion reaction and both half-cell reactions. The overall corrosion reaction for this system can be represented as: $$2\text{H}^+ + \text{M} \rightarrow \text{M}^{2+} + \text{H}_2$$ This reaction consists of two half-cell reactions: 1. Anodic (oxidation) reaction: $$\text{M} \rightarrow \text{M}^{2+} + 2\text{e}^-$$ 2. Cathodic (reduction) reaction: $$2\text{H}^+ + 2\text{e}^- \rightarrow \text{H}_2$$
02

Calculate corrosion current density

Next, we will calculate the corrosion current density ($$i_{\text{corr}}$$) using the Tafel equation, which relates the overpotential ($$\eta$$) and the logarithm of the current density: $$\eta_{\text{anodic}} = \beta_a \log{\frac{i_{\text{corr}}}{i_{0, \text{anodic}}}}$$ $$\eta_{\text{cathodic}} = \beta_c \log{\frac{i_{\text{corr}}}{i_{0, \text{cathodic}}}}$$ Since the system is at equilibrium, the anodic and cathodic overpotential will be equal: $$\eta_{\text{anodic}} = -\eta_{\text{cathodic}}$$ Substituting the values, we get: $$0.10 \log{\frac{i_{\text{corr}}}{10^{-12}}} = -(-0.15) \log{\frac{i_{\text{corr}}}{10^{-10}}}$$
03

Solve for corrosion current density

Now we solve the equation from Step 2 to find corrosion current density: $$0.10 \log{\frac{i_{\text{corr}}}{10^{-12}}} = 0.15 \log{\frac{i_{\text{corr}}}{10^{-10}}}$$ Divide both sides by 0.01 and combine logarithms: $$\log{\frac{i_{\text{corr}}}{10^{-12}}} - \log{\frac{i_{\text{corr}}}{10^{-10}}} = 15 - 10$$ $$\log{\frac{10^{-12}}{i_{\text{corr}}} \times \frac{i_{\text{corr}}}{10^{-10}}} = 5$$ Take the antilog of both sides: $$\frac{10^{-12}}{i_{\text{corr}}} \times \frac{i_{\text{corr}}}{10^{-10}} = 10^5$$ Solve for $$i_{\text{corr}}$$: $$i_{\text{corr}}^2 = 10^{-12} \times 10^{-10} \times 10^5 = 10^{-17}$$ $$i_{\text{corr}} = 10^{-8.5} \ \text{A/cm}^2$$
04

Convert corrosion current density to corrosion rate

To find the corrosion rate in mol/cm²·s, we'll divide corrosion current density by the Faraday constant (F = 96485 C/mol) and the number of electrons involved in the overall reaction (n = 2). From step 3, we have: $$i_{\text{corr}} = 10^{-8.5} \ \text{A/cm}^2$$ Now, divide by Faraday constant and number of electrons: $$\text{Corrosion rate} = \frac{10^{-8.5}\ \text{A/cm}^2}{2 \times 96485 \ \text{C/mol}}$$ $$\text{Corrosion rate} = 5.19 \times 10^{-15}\ \text{mol/cm}^2\text{s}$$ So, the corrosion rate of metal M is approximately $$5.19 \times 10^{-15}\ \text{mol/cm}^2\text{s}$$.
05

Calculate corrosion potential

To find the corrosion potential ($$E_{\text{corr}}$$), we use the Nernst equation: $$E_{\text{corr}} = \frac{-\eta}{\beta}$$ For the anodic half-cell reaction, this would be: $$E_{\text{corr}} = \frac{-\eta_{\text{anodic}}}{\beta_a}$$ $$E_{\text{corr}} = \frac{-0.10\log{\frac{10^{-8.5}}{10^{-12}}}}{0.10}$$ $$E_{\text{corr}} = -\log{\frac{10^{-8.5}}{10^{-12}}}$$ $$E_{\text{corr}} = -(-3.5)$$ $$E_{\text{corr}} = 3.5 \ \text{V}$$ (relative to the hydrogen standard electrode) So, the corrosion potential for this reaction is 3.5 V relative to the hydrogen standard electrode.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Electrochemical Corrosion
Electrochemical corrosion is a common problem where metal surfaces deteriorate due to chemical reactions with their environment. It occurs when a metal forms a voltaic cell with its environment, resulting in the flow of electrons from the metal to the electrolyte. This process typically involves an anodic reaction, where the metal is oxidized and loses electrons, and a cathodic reaction, where a reduction occurs, and electrons are gained.

Let’s take a divalent metal M, for instance. In an environment containing hydrogen ions, the metal may corrode via an electrochemical reaction. Oxidation happens at the metal's surface, releasing metal ions into solution and electrons into the metal. These electrons then travel to another spot on the metal, or to another electrode, where they reduce hydrogen ions into hydrogen gas. As this process continues, the metal is gradually consumed.
Deciphering the Tafel Equation
The Tafel equation is crucial for understanding the kinetics of electrochemical reactions during corrosion. It describes the relationship between the overpotential, which is the potential deviation from the equilibrium potential, and the current density. The equation is given by:
\[\begin{equation}\eta = \beta \log\left(\frac{i}{i_0}\right)\end{equation}\]
where \(\eta\) is the overpotential, \(\beta\) is the Tafel slope (indicative of the rate of the reaction), \(i\) is the current density, and \(i_0\) is the exchange current density (a measure of the reaction rate when there is no net current).

In corrosion science, both the anodic and cathodic branches of the Tafel plot are used to extrapolate the corrosion current density. This allows us to estimate the rate of corrosion without having to measure it directly in an aggressive environment, instead using controlled experimental conditions.
Applying the Nernst Equation
The Nernst equation is another cornerstone of electrochemistry that is employed to calculate the equilibrium potential of an electrode reaction based on concentration. It is an expression for the potential of a chemical reaction to move towards equilibrium. Mathematically, the Nernst equation is written as:\[\begin{equation}E = E^\circ - \frac{RT}{nF} \ln\left(\frac{[\text{products}]}{[\text{reactants}]}\right)\end{equation}\]
where \(E\) is the electrode potential, \(E^\circ\) is the standard electrode potential, \(R\) is the gas constant, \(T\) is the temperature in Kelvin, \(n\) is the number of moles of electrons, and \(F\) is the Faraday’s constant.

In corrosion calculations, we often use a simplified form of this equation to find the corrosion potential. By comparing the corrosion potential to other potentials, one can infer how noble or active a metal is under specific conditions; the more negative the potential, the more active the metal behaves.
Assessing Corrosion Current Density
Corrosion current density is a critical parameter in electrochemical corrosion, representing the amount of electrical current per unit area that passes through the electrolyte as a result of corrosion. It is denoted by \(i_{\text{corr}}\) and is usually measured in amperes per square centimeter (A/cm²).

The corrosion current density is directly related to the rate of metal dissolution in the case of anodic reactions, or the rate of reduction reaction in cathodic processes. In other words, it tells us how quickly a metal is corroding in a given environment. By using the previously mentioned Tafel equation and experimental data, we can calculate this important value.

Once the corrosion current density is known, it can be converted to the corrosion rate by considering the number of electrons transferred and the Faraday constant. This provides a quantitative measurement of how much metal is lost over time due to corrosion, which is essential for predicting the longevity and durability of metal structures in corrosive environments.

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Most popular questions from this chapter

(a) Cite the major differences between activation and concentration polarizations. (b) Under what conditions is activation polarization rate controlling? (c) Under what conditions is concentration polarization rate controlling?

Briefly explain why, for a small anode-tocathode area ratio, the corrosion rate will be higher than for a large ratio.

(a) Write the possible oxidation and reduction half-reactions that occur when magnesium is immersed in each of the following solutions: (i) HCl, (ii) an HCl solution containing dissolved oxygen, and (iii) an HCl solution containing dissolved oxygen and, in addition, \(\mathrm{Fe}^{2+}\) ions. (b) In which of these solutions would you expect the magnesium to oxidize most rapidly? Why?

(a) From the galvanic series (Table 17.2), cite three metals or alloys that may be used to galvanically protect 304 stainless steel in the active state. (b) As Concept Check 17.4(b) notes, galvanic corrosion is prevented by making an electrical contact between the two metals in the couple and a third metal that is anodic to the other two. Using the galvanic series, name one metal that could be used to protect a copper-aluminum galvanic couple.

An electrochemical cell is constructed such that on one side a pure nickel electrode is in contact with a solution containing \(\mathrm{Ni}^{2+}\) ions at a concentration of \(3 \times 10^{-3} M\). The other cell half consists of a pure Fe electrode that is immersed in a solution of \(\mathrm{Fe}^{2+}\) ions having a concentration of \(0.1 M\). At what temperature will the potential between the two electrodes be \(+0.140 \mathrm{~V} ?\)

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