What is the composition, in atom percent, of an alloy that contains \(99.7 \mathrm{lb}_{\mathrm{m}}\) copper, \(102 \mathrm{lb}_{\mathrm{m}}\) zinc, and \(2.1 \mathrm{lb}_{\mathrm{m}}\) lead?

Question: Determine the atom percent composition of an alloy containing 99.7 lbm of copper, 102 lbm of zinc, and 2.1 lbm of lead. Answer: To find the atom percent composition of each element in the alloy, follow these steps: 1. Convert the mass of each element to moles using their respective molar masses. 2. Calculate the total moles present in the alloy by adding the moles of each element. 3. Find the atom percent composition of each element by dividing their individual moles by the total moles and multiplying by 100. Copper atom % = \(\frac{\text{Copper moles}}{\text{Total moles}} \times 100\) Zinc atom % = \(\frac{\text{Zinc moles}}{\text{Total moles}} \times 100\) Lead atom % = \(\frac{\text{Lead moles}}{\text{Total moles}} \times 100\) With these calculations, you can determine the atom percent composition of copper, zinc, and lead in the alloy.