The preexponential and activation energy for the diffusion of iron in cobalt are \(1.1 \times 10^{-5}\) \(\mathrm{m}^{2} / \mathrm{s}\) and \(253,300 \mathrm{~J} / \mathrm{mol}\), respectively. At what temperature will the diffusion coefficient have a value of \(2.1 \times 10^{-14} \mathrm{~m}^{2} / \mathrm{s}\) ?

Short Answer

Expert verified
Answer: The temperature at which the diffusion coefficient will have a value of \(2.1 × 10^{-14} \mathrm{m}^2/ \mathrm{s}\) is approximately 720 K.

Step by step solution

01

Write the Arrhenius equation

The Arrhenius equation is given by: D = D0 * exp(-Ea / (R * T)) where D is the diffusion coefficient, D0 is the preexponential factor, Ea is the activation energy, R is the ideal gas constant, and T is the temperature in Kelvin.
02

Rearrange the equation for T

Rearrange the Arrhenius equation to solve for T: T = -Ea / (R * ln(D / D0))
03

Plug in the given values

Plug in the given values for D, D0, and Ea, and use the value of R as \(8.314 \mathrm{J} \cdot \mathrm{mol}^{-1} \cdot \mathrm{K}^{-1}\): T = -253300 J/mol / (8.314 J/mol·K * ln(2.1×10^{-14} m^2/s / 1.1×10^{-5} m^2/s))
04

Solve the equation for T

Simplify and solve for T: T = -253300 J/mol / (-42.954 * 8.314 J/mol·K) ≈ 720 K The temperature at which the diffusion coefficient will have a value of \(2.1 × 10^{-14} \mathrm{m}^2/ \mathrm{s}\) is approximately 720 K.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffusion Coefficient
The diffusion coefficient, denoted as D, quantifies how fast a substance such as atoms or molecules diffuse through a medium. In the context of our exercise, it reflects the rate at which iron atoms spread within cobalt. An intriguing aspect of the diffusion coefficient is that it's not a constant value; rather, it changes with temperature and the properties of the materials involved.

To understand the diffusion coefficient more clearly, consider it the 'ease' with which particles move around. If the value of D is high, the particles are moving more freely and quickly. Conversely, if D is low, the movement occurs much slower. This concept allows us to predict and control material behaviors, especially during processes like alloy formation or the tempering of metals.

Relation with Arrhenius Equation

The Arrhenius equation links the diffusion coefficient to temperature and activation energy. By manipulating this relationship, we can infer how changes in temperature will affect diffusion rates, which is crucial for designing industrial processes or understanding geological formations.
Activation Energy
Activation energy (Ea) is the minimum energy required for a reaction to occur. It's an essential concept in the realm of chemistry and material sciences, as it pertains to various processes, including diffusion. When you imagine atoms hopping from one location to another, they need to overcome a certain energy barrier - this is the activation energy.

The higher the activation energy, the slower the diffusion process because fewer atoms have the energy to overcome this barrier at any given temperature. This can be visualized as a high mountain pass that only the most energetic skiers can traverse. The Arrhenius equation incorporates activation energy to help us determine how temperature changes will impact the speed of diffusion, with a higher Ea implying a greater sensitivity to temperature changes.

Crucial to Kinetics

Understanding activation energy is vital to mastering kinetics, which involves the rates at which reactions occur. It's a fundamental aspect that allows scientists and engineers to tailor materials and reactions by manipulating temperatures to achieve desired diffusion rates.
Temperature Dependence of Diffusion
Temperature plays a significant role in the diffusion process, affecting the diffusion coefficient. According to the Arrhenius equation used in our exercise, an increase in temperature will lead to an exponential increase in the diffusion coefficient. This is related to the fact that at higher temperatures, atoms have more kinetic energy and can more easily surmount the activation energy barrier to move from one spot to another.

This temperature dependence is why you'll find that processes like the hardening of steel or baking a cake are highly sensitive to temperature. Get the temperature wrong, and the microstructures won't form correctly or the cake won't have the right texture. For our iron-in-cobalt diffusion example, knowing the specific temperature at which a certain diffusion coefficient is achieved allows for precise control over the process.

Exponential Relationship

The relationship between temperature and diffusion is not linear but exponential. That means a slight change in temperature can lead to a dramatic change in the diffusion rate. In practical applications, this concept is critical for controlling material properties during manufacturing or treatment processes.

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Most popular questions from this chapter

Briefly explain the concept of steady state as it applies to diffusion.

For a steel alloy it has been determined that a carburizing heat treatment of 10 -h duration will raise the carbon concentration to \(0.45 \mathrm{wt} \%\) at a point \(2.5 \mathrm{~mm}\) from the surface. Estimate the time necessary to achieve the same concentration at a 5.0-mm position for an identical steel and at the same carburizing temperature.

Nitrogen from a gaseous phase is to be dif? fused into pure iron at \(700^{\circ} \mathrm{C}\). If the surface concentration is maintained at \(0.1 \mathrm{wt} \% \mathrm{~N}\) what will be the concentration \(1 \mathrm{~mm}\) from the surface after \(10 \mathrm{~h}\) ? The diffusion coefficient for nitrogen in iron at \(700^{\circ} \mathrm{C}\) is \(2.5 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{s}\).

An FCC iron-carbon alloy initially containing \(0.35 \mathrm{wt} \% \mathrm{C}\) is exposed to an oxygen-rich and virtually carbon-free atmosphere at \(1400 \mathrm{~K}\) (1127 \(\left.^{\circ} \mathrm{C}\right)\). Under these circumstances the carbon diffuses from the alloy and reacts at the surface, with the oxygen in the atmosphere; that is, the carbon concentration at the surface position is maintained essentially at \(0 \mathrm{wt} \%\) C. (This process of carbon depletion is termed decarburization.) At what position will the carbon concentration be \(0.15 \mathrm{wt} \%\) after a 10 -h treatment? The value of \(D\) at \(1400 \mathrm{~K}\) is \(6.9 \times 10^{-11} \mathrm{~m}^{2} / \mathrm{s}\).

The steady-state diffusion flux through a metal plate is \(5.4 \times 10^{-10} \mathrm{~kg} / \mathrm{m}^{2} \cdot \mathrm{s}\) at a temperature of \(727^{\circ} \mathrm{C}(1000 \mathrm{~K})\) and when the concentration gradient is \(-350 \mathrm{~kg} / \mathrm{m}^{4} .\) Calculate the diffusion flux at \(1027^{\circ} \mathrm{C}(1300 \mathrm{~K})\) for the same concentration gradient and assuming an activation energy for diffusion of \(125,000 \mathrm{~J} / \mathrm{mol}\).

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