Chapter 6: Problem 54
Cite five factors that lead to scatter in measured material properties.
Chapter 6: Problem 54
Cite five factors that lead to scatter in measured material properties.
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Get started for freeUsing the solution to Problem \(6.13\), rank the magnitudes of the moduli of elasticity for the following hypothetical X, Y, and Z materials from the greatest to the least. The appropriate \(A, B\), and \(n\) parameters (Equation \(6.25)\), for these three materials are shown in the following table; they yield \(E_{N}\) in units of electron volts and \(r\) in nanometers: $$ \begin{array}{cccc} \hline \text { Material } & \boldsymbol{A} & \boldsymbol{B} & \boldsymbol{n} \\\ \hline \mathrm{X} & 2.5 & 2.0 \times 10^{-5} & 8 \\ \mathrm{Y} & 2.3 & 8.0 \times 10^{-6} & 10.5 \\ \mathrm{Z} & 3.0 & 1.5 \times 10^{-5} & 9 \\ \hline \end{array} $$
Using the data in Problem \(6.29\) and Equations 6.15, 6.16, and 6.18a, generate a true stress-true strain plot for aluminum. Equation \(6.18\) a becomes invalid past the point at which necking begins; therefore, measured diameters are given in the following table for the last four data points, which should be used in true stress computations. $$ \begin{array}{cccccc} \hline \text {Load} & & \text {Length} & & \text {Diameter} \\ \hline \boldsymbol{N} & \boldsymbol{l b}_{f} & \boldsymbol{m m} & \text { in. } & {\boldsymbol{m m}} & \text { in. } \\ \hline 46,100 & 10,400 & 56.896 & 2.240 & 11.71 & 0.461 \\ 44,800 & 10,100 & 57.658 & 2.270 & 11.26 & 0.443 \\ 42,600 & 9,600 & 58.420 & 2.300 & 10.62 & 0.418 \\ 36,400 & 8,200 & 59.182 & 2.330 & 9.40 & 0.370 \\ \hline \end{array} $$
A cylindrical rod of copper \((E=110 \mathrm{GPa}\), \(16 \times 10^{6}\) psi) having a yield strength of 240 MPa ( \(35,000 \mathrm{psi})\) is to be subjected to a load of \(6660 \mathrm{~N}\left(1500 \mathrm{lb}_{\mathrm{f}}\right)\). If the length of the rod is \(380 \mathrm{~mm}\) (15.0 in.), what must be the diameter to allow an elongation of \(0.50 \mathrm{~mm}\) \((0.020 \mathrm{in} .)\) ?
The following true stresses produce the corresponding true plastic strains for a brass alloy: $$ \begin{array}{cc} \hline \begin{array}{c} \text { True Stress } \\ \text { (psi) } \end{array} & \text { True Strain } \\ \hline 50,000 & 0.10 \\ 60,000 & 0.20 \\ \hline \end{array} $$ What true stress is necessary to produce a true plastic strain of \(0.25\) ?
Consider a cylindrical specimen of some hypothetical metal alloy that has a diameter of \(8.0 \mathrm{~mm}(0.31 \mathrm{in} .)\). A tensile force of \(1000 \mathrm{~N}\) \(\left(225 \mathrm{lb}_{\mathrm{f}}\right.\) ) produces an elastic reduction in diameter of \(2.8 \times 10^{-4} \mathrm{~mm}\left(1.10 \times 10^{-5} \mathrm{in}\right.\).). Compute the modulus of elasticity for this alloy, given that Poisson's ratio is \(0.30\).
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