Chapter 7: Problem 32
Experimentally, it has been observed for single crystals of a number of metals that the critical resolved shear stress \(\tau_{\text {crsss }}\) is a function of the dislocation density \(\rho_{D}\) as $$ \tau_{\text {crss }}=\tau_{0}+A \sqrt{\rho_{D}} $$ where \(\tau_{0}\) and \(A\) are constants. For copper, the critical resolved shear stress is \(2.10 \mathrm{MPa}\) (305 psi) at a dislocation density of \(10^{5} \mathrm{~mm}^{-2}\). If it is known that the value of \(A\) for copper is \(6.35\) \(\times 10^{-3} \mathrm{MPa} \cdot \mathrm{mm}(0.92 \mathrm{psi} \cdot \mathrm{mm})\), compute \(\tau_{\text {crss }}\) at a dislocation density of \(10^{7} \mathrm{~mm}^{-2}\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.