For each of edge, screw, and mixed dislocations, cite the relationship between the direction of the applied shear stress and the direction of dislocation line motion.

Short Answer

Expert verified
Answer: For edge dislocations, the dislocation line motion is perpendicular to the applied shear stress direction. In the case of screw dislocations, the dislocation line motion is parallel to the applied shear stress direction. For mixed dislocations, the direction of dislocation line motion depends on the angle between the applied shear stress direction and the dislocation line, and it consists of components in both edge and screw dislocation directions.

Step by step solution

01

Define different types of dislocations

An edge dislocation is a type of defect in a crystal lattice where an extra half-plane of atoms is inserted. A screw dislocation, on the other hand, is a defect caused by shear forces that twist the lattice such that lattice planes spiral around the dislocation. Mixed dislocations possess characteristics of both edge and screw dislocations.
02

Explain the relationship for edge dislocations

For an edge dislocation, the direction of dislocation line motion is perpendicular to both the dislocation line and the applied shear stress direction. The motion of the dislocation line will cause the extra half-plane of atoms to advance through the lattice, resulting in the material being deformed.
03

Explain the relationship for screw dislocations

In the case of a screw dislocation, the dislocation line motion is parallel to the applied shear stress direction. The motion of the dislocation line occurs by the sliding of one part of the crystal lattice relative to the other, resulting in a twisting effect in the lattice structure.
04

Explain the relationship for mixed dislocations

For mixed dislocations, the motion of the dislocation line will have components along both the edge and screw dislocation directions. The direction of dislocation line motion will depend on the applied shear stress direction, and the angle between the applied shear stress direction and the dislocation line determines the proportion of edge and screw character in the mixed dislocation. In conclusion, the direction of dislocation line motion is influenced by the type of dislocation as well as the direction of the applied shear stress. For edge dislocations, the motion is perpendicular to the applied shear stress direction, for screw dislocations it is parallel, and for mixed dislocations, it is determined by the angle between the applied shear stress direction and the dislocation line.

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Most popular questions from this chapter

Experimentally, it has been observed for single crystals of a number of metals that the critical resolved shear stress \(\tau_{\text {crsss }}\) is a function of the dislocation density \(\rho_{D}\) as $$ \tau_{\text {crss }}=\tau_{0}+A \sqrt{\rho_{D}} $$ where \(\tau_{0}\) and \(A\) are constants. For copper, the critical resolved shear stress is \(2.10 \mathrm{MPa}\) (305 psi) at a dislocation density of \(10^{5} \mathrm{~mm}^{-2}\). If it is known that the value of \(A\) for copper is \(6.35\) \(\times 10^{-3} \mathrm{MPa} \cdot \mathrm{mm}(0.92 \mathrm{psi} \cdot \mathrm{mm})\), compute \(\tau_{\text {crss }}\) at a dislocation density of \(10^{7} \mathrm{~mm}^{-2}\).

The lower yield point for an iron that has an average grain diameter of \(5 \times 10^{-2} \mathrm{~mm}\) is 135 MPa (19,500 psi). At a grain diameter of \(8 \times\) \(10^{-3} \mathrm{~mm}\), the yield point increases to \(260 \mathrm{MPa}\) \((37,500 \mathrm{psi})\). At what grain diameter will the lower yield point be \(205 \mathrm{MPa}(30,000 \mathrm{psi})\) ?

One slip system for the BCC crystal structure is \(\\{110\\}(111\rangle\). In a manner similar to Figure \(7.6 b\), sketch a \\{110\\}-type plane for the BCC structure, representing atom positions with circles. Now, using arrows, indicate two different \(\langle 111\rangle\) slip directions within this plane.

Explain the differences in grain structure for a metal that has been cold worked and one that has been cold worked and then recrystallized.

An uncold-worked brass specimen of average grain size \(0.008 \mathrm{~mm}\) has a yield strength of 160 MPa \((23,500\) psi). Estimate the yield strength of this alloy after it has been heated to \(600^{\circ} \mathrm{C}\) for \(1000 \mathrm{~s}\), if it is known that the value of \(k_{y}\) is \(12.0 \mathrm{MPa} \cdot \mathrm{mm}^{1 / 2}\left(1740 \mathrm{psi} \cdot \mathrm{mm}^{1 / 2}\right)\)

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