Chapter 10: Problem 31
Briefly explain why fine pearlite is harder and stronger than coarse pearlite, which in turn is harder and stronger than spheroidite.
Chapter 10: Problem 31
Briefly explain why fine pearlite is harder and stronger than coarse pearlite, which in turn is harder and stronger than spheroidite.
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Get started for freeBriefly cite the differences among pearlite, bainite, and spheroidite relative to microstructure and mechanical properties.
(a) For the solidification of nickel, calculate the critical radius \(r^{*}\) and the activation free energy \(\Delta G^{*}\) if nucleation is homogeneous. Values for the latent heat of fusion and surface free energy are \(-2.53 \times 10^{9} \mathrm{~J} / \mathrm{m}^{3}\) and \(0.255 \mathrm{~J} / \mathrm{m}^{2}\), respectively. Use the supercooling value found in Table 10.1. (b) Now, calculate the number of atoms found in a nucleus of critical size. Assume a lattice parameter of \(0.360 \mathrm{~nm}\) for solid nickel at its melting temperature.
Name the two stages involved in the formation of particles of a new phase. Briefly describe each.
For some transformation having kinetics that obey the Avrami equation (Equation 10.17), the parameter \(n\) is known to have a value of \(1.5 .\) If the reaction is \(25 \%\) complete after \(125 \mathrm{~s}\), howlong (total time) will it take the transformation to go to \(90 \%\) completion?
Briefly describe the simplest continuouscooling heat treatment procedure that would be used in converting a 4340 steel from one microstructure to another. (a) (Martensite \(+\) ferrite \(+\) bainite) to \((\) martensite \(+\) ferrite \(+\) pearlite \(+\) bainite \()\) (b) (Martensite + ferrite + bainite) to spheroidite (c) (Martensite \(+\) bainite \(+\) ferrite) to tempered martensite
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