Express cach of the following expressions using a single positive index: (a) \(x^{4} x^{7}\) (b) \(x^{2}(-x)\) (c) \(\frac{x^{2}}{x}\). (d) \(\frac{x^{-2}}{x^{-1}}\) (c) \(\left(x^{-2}\right)^{4}\) (f) \(\left(x^{-25} x^{-3.5}\right)^{2}\)

Short Answer

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Question: Express the following expressions using a single positive index: a) \(x^4 x^7\) b) \(x^2(-x)\) c) \(\frac{x^2}{x}\) d) \(\frac{x^{-2}}{x^{-1}}\) e) \(\left(x^{-2}\right)^{4}\) f) \(\left(x^{-25} x^{-3.5}\right)^{2}\) Answer: a) \(x^{11}\) b) \(x\) c) \(x\) d) \(x^{-1}\) e) \(x^{-8}\) f) \(x^{-57}\)

Step by step solution

01

Problem (a) Solution

We are given expression \(x^4 x^7\). Using the first property of exponents, we add the exponents: \(x^4 \cdot x^7 = x^{4 + 7} = x^{11}\).
02

Problem (b) Solution

We are given expression \(x^2(-x)\). We can rewrite \((-x)\) as \(x^{-1}\). Now, we can apply the first property of exponents: \(x^2 \cdot x^{-1} = x^{2 + (-1)} = x^{1} = x\).
03

Problem (c) Solution

We are given expression \(\frac{x^2}{x}\). Using the second property of exponents, we subtract the exponents: \(\frac{x^2}{x} = x^{2 - 1} = x^1=x\).
04

Problem (d) Solution

We are given expression \(\frac{x^{-2}}{x^{-1}}\). Using the second property of exponents, we have: \(\frac{x^{-2}}{x^{-1}} = x^{-2 - (-1)}= x^{-2+1} = x^{-1}\).
05

Problem (e) Solution

We are given expression \(\left(x^{-2}\right)^{4}\) . Using the third property of exponents, we have: \(\left(x^{-2}\right)^{4} = x^{-2 \cdot 4}=x^{-8}\).
06

Problem (f) Solution

We are given expression \(\left(x^{-25} x^{-3.5}\right)^{2}\). First, we simplify the expression inside the parentheses using the first property of exponents: \(x^{-25} x^{-3.5} = x^{-25 - 3.5} = x^{-28.5}\). Next, we apply the third property of exponents to find the final answer: \(\left(x^{-28.5}\right)^{2} = x^{-28.5 \cdot 2} = x^{-57}.\) We have now written all of the given expressions using a single positive index.

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