For each of the following pairs of polymers, do ( the following: (1) State whether it is possible to decide whether one polymer has a higher tensile modulus than the other; (2) if this is possible, note which has the higher tensile modulus and cite the reason(s) for your choice; and (3) if it is not possible to decide, state why. (a) Branched and atactic poly(vinyl chloride) with a weight-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\); linear and isotactic poly(vinyl chloride) having a weight-average molecular weight of \(75,000 \mathrm{~g} / \mathrm{mol}\) (b) Random styrene-butadiene copolymer with \(5 \%\) of possible sites crosslinked; block styrene-butadiene copolymer with \(10 \%\) of possible sites crosslinked (c) Branched polyethylene with a number-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\); atactic polypropylene with a number-average molecular weight of \(150,000 \mathrm{~g} / \mathrm{mol}\)

Short Answer

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Answer: a) Linear and isotactic poly(vinyl chloride) has a higher tensile modulus due to its more ordered and crystalline structure, as well as better packing efficiency from the linear chain arrangement. b) It is difficult to decide which styrene-butadiene copolymer has a higher tensile modulus without more information on the distribution and arrangement of the copolymer units. c) Branched polyethylene has a higher tensile modulus than atactic polypropylene due to its higher crystallinity and more ordered structure.

Step by step solution

01

a) Branched and atactic poly(vinyl chloride) vs linear and isotactic poly(vinyl chloride)

We can compare the tensile modulus of these two polymers because they have well-defined structures. The higher tensile modulus is observed in the linear and isotactic poly(vinyl chloride). The reasons for the higher tensile modulus are: 1. The isotactic structure leads to a more ordered and crystalline structure, which provides better mechanical properties. 2. The linear chain arrangement has better packing efficiency than the branched one, leading to a more rigid and resistant structure. Even though the linear and isotactic PVC has a lower molecular weight (75,000 g/mol) than the branched and atactic PVC (100,000 g/mol), its ordered and linear structure provides a higher tensile modulus.
02

b) Random styrene-butadiene copolymer vs block styrene-butadiene copolymer

It is difficult to decide which one of the given styrene-butadiene copolymers will have a higher tensile modulus without more information. The different crosslinking percentages (5% and 10%) alone are not enough to make a conclusion. The tensile modulus depends not only on the crosslinking but also on the distribution and arrangement of the styrene and butadiene units within the polymer, which is not provided in the problem.
03

c) Branched polyethylene vs atactic polypropylene

We can compare the tensile modulus of these two polymers because they have well-defined structures. The higher tensile modulus is observed in the branched polyethylene. The reasons for the higher tensile modulus are: 1. Polyethylene, in general, has higher crystallinity than atactic polypropylene. The crystalline structure provides better mechanical properties. 2. Polyethylene has a somewhat more ordered structure than atactic polypropylene which further contributes to the higher tensile modulus. Even though the branched polyethylene has a lower molecular weight (100,000 g/mol) than the atactic polypropylene (150,000 g/mol), its higher crystallinity and order will result in a higher tensile modulus.

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Most popular questions from this chapter

For each of the following pairs of polymers, plot and label schematic stress- strain curves on the same graph [i.e., make separate plots for parts (a) to \((\mathrm{c})]\) (a) Polyisoprene having a number-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\) and \(10 \%\) of available sites crosslinked; polyisoprene having a numberaverage molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\) and \(20 \%\) of available sites crosslinked (b) Syndiotactic polypropylene having a weightaverage molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\); atactic polypropylene having a weight- average molecular weight of \(75,000 \mathrm{~g} / \mathrm{mol}\) (c) Branched polyethylene having a numberaverage molecular weight of \(90,000 \mathrm{~g} / \mathrm{mol}\); heavily crosslinked polyethylene having a number- average molecular weight of \(90,000 \mathrm{~g} / \mathrm{mol}\)

Which of the following would you expect to be (-) elastomers and which thermosetting polymers at room temperature? Justify each choice. (a) Linear and highly crystalline polyethylene (b) Phenol-formaldehyde (c) Heavily crosslinked polyisoprene having a glass transition temperature of \(50^{\circ} \mathrm{C}\left(122^{\circ} \mathrm{F}\right)\) (d) Lightly crosslinked polyisoprene having a glass transition temperature of \(-60^{\circ} \mathrm{C}\left(-76^{\circ} \mathrm{F}\right)\) (e) Linear and partially amorphous poly(vinyl chloride)

On the basis of the curves in Figure \(15.5\), sketch schematic strain-time plots for the following polystyrene materials at the specified temperatures: (a) Crystalline at \(70^{\circ} \mathrm{C}\) (b) Amorphous at \(180^{\circ} \mathrm{C}\) (c) Crosslinked at \(180^{\circ} \mathrm{C}\) (d) Amorphous at \(100^{\circ} \mathrm{C}\).

Cite five important characteristics for polymers that are to be used in thin- film applications.

Why must fiber materials that are melt-spun and then drawn be thermoplastic? Cite two reasons.

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