Fifteen kilograms of polychloroprene is vulcanized with \(5.2 \mathrm{~kg}\) of sulfur. What fraction of the possible crosslink sites is bonded to sulfur crosslinks, assuming that, on the average, \(5.5\) sulfur atoms participate in each crosslink?

Short Answer

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Answer: To find the fraction of bonded crosslink sites, follow the given steps: 1. Calculate the moles of polychloroprene and sulfur: Moles of polychloroprene = 15,000 g ÷ 88.54 g/mol Moles of sulfur = 5.2 × 10³ g ÷ 256.48 g/mol 2. Calculate the number of crosslinks: Number of crosslinks = moles of sulfur ÷ 5.5 3. Calculate the fraction of bonded crosslink sites: Fraction of bonded crosslink sites = number of crosslinks ÷ moles of polychloroprene Substitute the values obtained in steps 1 and 2 to get the fraction of bonded crosslink sites.

Step by step solution

01

Find moles of polychloroprene and sulfur

First, we need to find the number of moles of polychloroprene and sulfur. To do this, we will use their respective molecular weight: Molecular weight of polychloroprene (C4H5Cl) = 88.54 g/mol Molecular weight of sulfur (S8) = 256.48 g/mol To find the moles of polychloroprene and sulfur, we will use the mass given in the problem and divide by the molecular weight: Moles of polychloroprene = \(\frac{15,000 \mathrm{~g}}{88.54 \mathrm{~g/mol}}\) Moles of sulfur = \(\frac{5.2 \times 10^3 \mathrm{~g}}{256.48 \mathrm{~g/mol}}\)
02

Calculate the number of crosslinks

Now that we have the moles of polychloroprene and sulfur, we can find the number of crosslinks. We are given that, on average, 5.5 sulfur atoms participate in each crosslink. Therefore, we will divide the moles of sulfur by 5.5 to find the number of crosslinks: Number of crosslinks = \(\frac{\text{moles of sulfur}}{5.5}\)
03

Calculate the fraction of bonded crosslink sites

We can now calculate the fraction of the possible crosslink sites that are bonded to sulfur crosslinks. To do this, we will divide the number of crosslinks (from Step 2) by the moles of polychloroprene (from Step 1): Fraction of bonded crosslink sites = \(\frac{\text{number of crosslinks}}{\text{moles of polychloroprene}}\) Substitute the values obtained in Steps 1 and 2 to get the fraction of bonded crosslink sites.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Crosslinking in Polymer Science
Crosslinking in polymer science is a chemical process where individual polymer chains are linked together to form a three-dimensional network. This process can significantly alter the physical properties of the original polymer, often leading to increased strength, elasticity, and durability. Traditional rubber, for example, becomes less sticky and more durable after vulcanization, which is a form of crosslinking. During the vulcanization of polychloroprene, sulfur atoms act as a bridge between polymer chains, creating crosslinks.

In the case of vulcanization, the amount of sulfur used and the number of sulfur atoms that participate in each crosslink are critical factors that determine the extent of crosslinking. The practical consequence of these crosslinks is evident in products like car tires, where improved mechanical properties are essential for performance and safety.
Calculation of Moles in Chemistry
Understanding how to calculate moles is a foundation in chemistry that allows us to measure quantities of substances based on their molecular weights. Moles provide a bridge between the microscopic world of atoms and molecules and the macroscopic world of grams and kilograms that we can measure in the lab. The mole concept is vital in stoichiometry as it enables chemists to predict how much of a substance will react with another.

The number of moles of a substance is calculated by dividing the mass of the substance (in grams) by its molecular weight (in grams per mole). In the context of our exercise, by determining the moles of polychloroprene and sulfur, we can deduce how they react during the vulcanization process. By knowing the number of moles, we can predict the extent of crosslinking and ultimately, the properties of the final vulcanized product.
Molecular Weight Determination
Determining the molecular weight of a substance is crucial for various calculations in chemistry, including the computation of moles. Molecular weight, also called molecular mass, is the sum of the atomic weights of all atoms in a molecule. It is generally expressed in units of grams per mole (g/mol).

For polymers like polychloroprene, the repeating unit's molecular weight is calculated by adding the atomic weights of each constituent atom. In our exercise, we use the molecular weight of polychloroprene and sulfur to find out how many moles of each are present. Accurate determination of molecular weights is essential because it affects the stoichiometry of chemical reactions and the properties of materials, which, in turn, impacts how substances interact in a given application, such as in the vulcanization of rubber.

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Most popular questions from this chapter

Cite four factors that determine what fabrication technique is used to form polymeric materials.

Which of the following polyethylene thin films would have the better mechanical characteristics? (1) Those formed by blowing. (2) Those formed by extrusion and then rolled. Why?

The tensile strength and number-average mo( lecular weight for two polyethylene materials are as follows: $$ \begin{array}{cc} \hline \begin{array}{c} \text { Tensile } \\ \text { Strength (MPa) } \end{array} & \begin{array}{c} \text { Number-Average } \\ \text { Molecular Weight (g/mol) } \end{array} \\ \hline 90 & 20,000 \\ \hline 180 & 40,000 \\ \hline \end{array} $$ Estimate the number-average molecular weight that is required to give a tensile strength of \(140 \mathrm{MPa}\).

Which of the following would you expect to be (-) elastomers and which thermosetting polymers at room temperature? Justify each choice. (a) Linear and highly crystalline polyethylene (b) Phenol-formaldehyde (c) Heavily crosslinked polyisoprene having a glass transition temperature of \(50^{\circ} \mathrm{C}\left(122^{\circ} \mathrm{F}\right)\) (d) Lightly crosslinked polyisoprene having a glass transition temperature of \(-60^{\circ} \mathrm{C}\left(-76^{\circ} \mathrm{F}\right)\) (e) Linear and partially amorphous poly(vinyl chloride)

Would you expect the tensile strength of polychlorotrifluoroethylene to be greater than, the same as, or less than that of a polytetrafluoroethylene specimen having the same molecular weight and degree of crystallinity? Why?

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