For each of the following pairs of polymers do the following: (1) State whether it is possible to determine whether one polymer has a higher melting temperature than the other; (2) if it is possible, note which has the higher melting temperature and then cite reason(s) for your choice; and (3) if it is not possible to decide, then state why. (a) Branched polyethylene having a numberaverage molecular weight of \(850,000 \mathrm{~g} / \mathrm{mol}\); linear polyethylene having a number-average molecular weight of \(850,000 \mathrm{~g} / \mathrm{mol}\) (b) Polytetrafluoroethylene having a density of \(2.14 \mathrm{~g} / \mathrm{cm}^{3}\) and a weight-average molecular weight of \(600,000 \mathrm{~g} / \mathrm{mol}\); PTFE having a density of \(2.20\) \(\mathrm{g} / \mathrm{cm}^{3}\) and a weight-average molecular weight of \(600,000 \mathrm{~g} / \mathrm{mol}\) (c) Linear and syndiotactic poly(vinyl chloride). having a number-average molecular weight of \(500,000 \mathrm{~g} / \mathrm{mol}\); linear polyethylene having a numberaverage molecular weight of \(225,000 \mathrm{~g} / \mathrm{mol}\) (d) Linear and syndiotactic polypropylene having a weight-average molecular weight of 500,000 \(\mathrm{g} / \mathrm{mol}\); linear and atactic polypropylene having a weight-average molecular weight of \(750,000 \mathrm{~g} / \mathrm{mol}\)

Short Answer

Expert verified
Answer: Linear and syndiotactic poly(vinyl chloride) (PVC) are expected to have a higher melting temperature than linear polyethylene due to the presence of a polar chlorine atom in PVC leading to stronger intermolecular forces.

Step by step solution

01

(a) Branched polyethylene vs. linear polyethylene

For both branched and linear polyethylene, the number-average molecular weight is \(850,000\, \mathrm{g} / \mathrm{mol}\). Since both polymers have the same molecular weight and chemical composition, it is not possible to determine which one has a higher melting temperature based on the information provided. We need more information such as the degree of branching or crystallinity to make a decision.
02

(b) Polytetrafluoroethylene (PTFE) with different densities

Both PTFE samples have the same weight-average molecular weight of \(600,000\, \mathrm{g} / \mathrm{mol}\), but different densities: \(2.14\, \mathrm{g} / \mathrm{cm}^{3}\) and \(2.20\, \mathrm{g} / \mathrm{cm}^{3}\). The PTFE sample with higher density (\(2.20\, \mathrm{g} / \mathrm{cm}^{3}\)) has a more compact structure, leading to stronger intermolecular forces and, consequently, a higher melting temperature. Thus, the PTFE with density of \(2.20\, \mathrm{g} / \mathrm{cm}^{3}\) is likely to have a higher melting temperature.
03

(c) Linear and syndiotactic poly(vinyl chloride) vs. linear polyethylene

For this pair of polymers, the linear and syndiotactic poly(vinyl chloride) (PVC) has a number-average molecular weight of \(500,000\, \mathrm{g} / \mathrm{mol}\), while the linear polyethylene has a lower molecular weight of \(225,000\, \mathrm{g} / \mathrm{mol}\). Comparing the two polymers by their chemical structures, PVC has a polar chlorine atom in its repeating unit, which can lead to stronger intermolecular forces compared to linear polyethylene. Therefore, linear and syndiotactic PVC are expected to have a higher melting temperature than linear polyethylene.
04

(d) Linear and syndiotactic polypropylene vs. linear and atactic polypropylene

For this comparison, both the linear and syndiotactic polypropylene and the linear and atactic polypropylene have different weight-average molecular weights: \(500,000\, \mathrm{g} / \mathrm{mol}\) and \(750,000\, \mathrm{g} / \mathrm{mol}\), respectively. Syndiotactic polypropylene has a more ordered structure compared to atactic polypropylene, leading to increased crystallinity and stronger intermolecular forces. Therefore, even though the atactic polypropylene has a higher molecular weight, the linear and syndiotactic polypropylene are expected to have a higher melting temperature due to their more ordered structure and increased crystallinity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polymer Crystallinity

Understanding the concept of polymer crystallinity is crucial when predicting the melting temperature of polymers. Crystallinity refers to the degree to which the molecules in a polymer are orderly packed. In polymers with higher crystallinity, the regular arrangement of their long-chain molecules allows for strong intermolecular interactions and thus, increases the melting temperature. This is because a greater amount of energy is required to disturb the orderly structure and cause the polymer to transition from a solid to a liquid state.

For instance, in the case of polypropylene, the structure of the molecules significantly affects its crystallinity. Linear and syndiotactic polypropylene, which have a more regular arrangement of molecules, will exhibit higher crystallinity compared to linear and atactic polypropylene that has a random arrangement. As a result, the melting temperature of the more crystalline syndiotactic polypropylene will be higher than that of the atactic form, despite any differences in their molecular weights.

Molecular Weight of Polymers

The molecular weight of polymers plays a significant role in determining their physical properties, including the melting temperature. Generally, a higher molecular weight implies longer polymer chains, which can lead to increased van der Waals forces between the chains. Thus, generally, polymers with higher molecular weights require higher temperatures to melt because more energy is needed to overcome these forces.

However, it's important to note that molecular weight is not the sole determinant of melting temperature. As the exercise solution indicated, when comparing polymers of similar molecular weights, such as branched and linear polyethylene both at 850,000 g/mol, other structural factors like the degree of branching or crystallinity must be considered. These structural aspects can affect the ease with which the chains slide past one another, thereby influencing the melting temperature.

Intermolecular Forces in Polymers

Intermolecular forces in polymers include van der Waals forces, hydrogen bonding, and dipole-dipole interactions. These forces significantly affect the thermal and mechanical behaviors of polymers, including their melting temperatures. In polymers such as Polytetrafluoroethylene (PTFE), which contains highly electronegative fluorine atoms, the intermolecular forces are relatively strong due to the presence of dipole-dipole interactions. As a result, a higher temperature is needed to overcome these interactions during melting.

In the example provided, PTFE with a higher density suggests tighter packing and stronger intermolecular forces, leading to a greater melting temperature in comparison to a less dense PTFE with identical molecular weight. Such comparisons highlight how minute changes in molecular structure or composition can result in significant differences in the properties of polymers.

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Most popular questions from this chapter

Why must fiber materials that are melt-spun and then drawn be thermoplastic? Cite two reasons.

Which of the following polymers would be suit( able for the fabrication of cups to contain hot coffee: polyethylene, polypropylene, poly(vinyl chloride), PET polyester, and polycarbonate. Why?

For each of the following pairs of polymers, do ( the following: (1) State whether it is possible to decide whether one polymer has a higher tensile modulus than the other; (2) if this is possible, note which has the higher tensile modulus and cite the reason(s) for your choice; and (3) if it is not possible to decide, state why. (a) Branched and atactic poly(vinyl chloride) with a weight-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\); linear and isotactic poly(vinyl chloride) having a weight-average molecular weight of \(75,000 \mathrm{~g} / \mathrm{mol}\) (b) Random styrene-butadiene copolymer with \(5 \%\) of possible sites crosslinked; block styrene-butadiene copolymer with \(10 \%\) of possible sites crosslinked (c) Branched polyethylene with a number-average molecular weight of \(100,000 \mathrm{~g} / \mathrm{mol}\); atactic polypropylene with a number-average molecular weight of \(150,000 \mathrm{~g} / \mathrm{mol}\)

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Nylon 6,6 may be formed by means of a condensation polymerization reaction in which hexamethylene diamine \(\left[\mathrm{NH}_{2}-\left(\mathrm{CH}_{2}\right)_{6}-\mathrm{NH}_{2}\right]\) and adipic acid react with one another with the formation of water as a by- product. What masses of hexamethylene diamine and adipic acid are necessary to yield \(20 \mathrm{~kg}\) of completely linear nylon \(6,6 ?\) (Note: The chemical equation for this reaction is the answer to Concept Check 15.12.)

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