Convert the \([110]\) and \([00 \overline{1}]\) directions into the four-index Miller-Bravais scheme for hexagonal unit cells.

Short Answer

Expert verified
Answer: The four-index Miller-Bravais representations for the given directions are [1 1 -2 0] for [110] and [0 0 0 -1] for [00-1].

Step by step solution

01

Write down the conversion rules for the Miller to Miller-Bravais scheme

Write down the conversion rules for moving from the Miller indices (h, k, l) to the Miller-Bravais indices (u, v, t, w). 1. \(u = h\) 2. \(v = k\) 3. \(t = -(h+k)\) 4. \(w = l\)
02

Convert the [110] direction to the Miller-Bravais scheme

Apply the conversion rules to the given direction. 1. For the \([110]\) direction, we have h=1, k=1, and l=0. 2. Using the conversion rules, we get: u = 1 v = 1 t = -(1 + 1) = -2 w = 0 3. Therefore, the \([110]\) direction in the four-index Miller-Bravais scheme is \([1\,1\,\overline{2}\,0]\).
03

Convert the [00-1] direction to the Miller-Bravais scheme

Apply the conversion rules to the given direction. 1. For the \([00\overline{1}]\) direction, we have h=0, k=0, and l=-1. 2. Using the conversion rules, we get: u = 0 v = 0 t = -(0 + 0) = 0 w = -1 3. Therefore, the \([00\overline{1}]\) direction in the four-index Miller-Bravais scheme is \([0\,0\,0\,\overline{1}]\).

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