A sheet of BCC iron \(2-\mathrm{mm}\) thick was exposed to a carburizing gas atmosphere on one side and a decarburizing atmosphere on the other side at \(675^{\circ} \mathrm{C}\). After reaching steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces of the sheet were determined to be \(0.015\) and \(0.0068\) wt \(\%\), respectively. Compute the diffusion coefficient ifthe diffusion flux is \(7.36 \times 10^{-9} \mathrm{~kg} / \mathrm{m}^{2}+\mathrm{s}\). Hint: Use Equation \(4.9\) to convert the concentrations from weight percent to kilograms of carbon per cubic meter of iron.

Short Answer

Expert verified
Answer: The diffusion coefficient of carbon in a sheet of BCC iron is 1.22 * 10^{-11} m²/s.

Step by step solution

01

Convert given concentrations to kgs of C per cubic meter of iron

First, let's convert the given carbon concentrations from weight percent to kgs of carbon per cubic meter of iron using Equation 4.9. This will be needed in later calculations. Equation 4.9: C = (wt% C / 100) * (rho_fe / MC) where C is the carbon concentration in kgs of carbon per cubic meter of iron, wt% C is the weight percent of carbon, rho_fe = 7874 kg/m³ is the density of BCC iron, and MC = 55.85 g/mol (0.05585 kg/mol) is the molar mass of iron. For surface 1: C1 = (0.015 / 100) * (7874 / 0.05585) C1 = 2.108 kg of C/m³ For surface 2: C2 = (0.0068 / 100) * (7874 / 0.05585) C2 = 0.903 kg of C/m³
02

Apply Fick's first law of diffusion

We are given the diffusion flux, J, and we need to find the diffusion coefficient, D. We can use Fick's first law of diffusion which relates the diffusion flux to the diffusion coefficient and the concentration gradient: J = -D * (dC/dx) Rearrange the equation to solve for D: D = -J / (dC/dx) Since we have the two carbon concentrations (C1 and C2) and the thickness of the sheet (2 mm), we can calculate the concentration gradient as follows: dC/dx = (C2 - C1)/(L) where: dC/dx is the concentration gradient, C1 and C2 are the carbon concentrations at the two surfaces, and L = 2 mm = 0.002 m (converted to meters) is the thickness of the sheet. dC/dx = (0.903 - 2.108) / 0.002 dC/dx = -601.5 kg of C/m³-m
03

Calculate the diffusion coefficient

Now, we can use the calculated values for J and dC/dx to find the diffusion coefficient D. D = -J / (dC/dx) D = -(-7.36 * 10^{-9} kg/(m².s)) / (-601.5 kg of C/m³-m) D = 1.22 * 10^{-11} m²/s The diffusion coefficient is 1.22 * 10^{-11} m²/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fick's First Law of Diffusion
When trying to comprehend the journey of atoms or molecules as they invade each other's spaces within materials, an equation known as Fick's First Law of Diffusion is indispensable. Imagine a crowded room where everyone wants to move around. Molecules act much the same, but instead of seeking fresh conversations, they move from areas of high concentration to low concentration. Fick's Law gives us a way to predict this movement.

The principle is elegantly simple: the thicker the crowd (higher concentration of particles), and the larger the room (the material in which they're moving), the greater the flow of people from one area to another. Formally, the diffusion flux, denoted by the symbol J, which measures the amount of substance that will flow through a unit area during a unit time interval, is proportional to the concentration gradient. Mathematically, it is represented as:
\[J = -D \frac{dC}{dx}\]
Here, \(J\) is the diffusion flux, \(D\) is the diffusion coefficient, and \(\frac{dC}{dx}\) is the rate at which concentration, C, changes with position, x. The minus sign indicates that diffusion occurs in the direction of decreasing concentration. Understanding this law is pivotal for solving a wide range of real-world problems in material science, such as predicting how fast a material will corrode, how long it will take for a flavor to spread through a food product, or how to manage the carbon concentration in steel during processing.
Carbon Concentration Gradient
Now let's zoom in on the concept of a carbon concentration gradient. Much like hills that slope upwards or downwards, a concentration gradient is a slope, but for particles—carbon atoms, in our scenario. It defines how the concentration of carbon varies from one point to another within the iron sheet. This variation is the driving force for the diffusion process.

Visualizing the Concentration Gradient

To visualize it, picture spreading a thin layer of sugar on one side of a bread slice, representing higher concentration, nothing on the other side, representing lower concentration, and observing the sugar slowly spread through the bread—the sugar's movement represents carbon atoms diffusing across the iron sheet. Mathematically, the gradient is defined as the change in concentration over a certain distance:\[\frac{dC}{dx} = \frac{C_2 - C_1}{L}\]
in which \(C_1\) and \(C_2\) are the carbon concentrations on each side of the iron sheet, and L is the thickness of the sheet. A steeper concentration gradient means a stronger 'slope' for atoms to 'roll down', which in turn means a faster diffusion process. Thus, it's crucial for students to grasp how to calculate the gradient, in order to predict how quickly carbon will homogenize throughout the material.
Mass Transport in Materials
Lastly, let's integrate these concepts into a broader perspective known as mass transport in materials. It's all about understanding how particles move within solids, liquids, and gases. Consider it akin to traffic flow on highways, or the movement of water through underground aquifers.

In the context of our exercise with carbon in iron, we're dealing with mass transport within a solid. Factors such as the presence of other elements, the temperature, and the texture of the material can greatly influence this process. The temperature, especially, acts like a 'volume knob' for the molecular movement: higher temperatures generally increase the speed of particles, facilitating quicker diffusion.

Engineers and scientists must understand these principles to design materials with desired qualities. For instance, by controlling the carbon content in steel, they can adjust its hardness, strength, and ductility. Whether it's fortifying the beams of skyscrapers or refining the edge of a scalpel, the principles of diffusion and concentration gradients are at work, directing the symphony of atoms that create materials with specific, tailored properties.

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Most popular questions from this chapter

A sheet of steel \(2.5-\mathrm{mm}\) thick has nitrogen atmospheres on both sides at \(900^{\circ} \mathrm{C}\) and is permitted to achieve a steady-state diffusion condition. The diffusion coefficient for nitrogen in steel at this temperature is \(1.85 \times 10^{-10} \mathrm{~m}^{2} / \mathrm{s}\), and the diffusion flux is found to be \(1.0 \times 10^{-7} \mathrm{~kg} / \mathrm{m}^{2} \cdot\) s. Also, it is known that the concentration of nitrogen in the steel at the high-pressure surface is \(2 \mathrm{~kg} / \mathrm{m}^{3}\). How far into the sheet from this high-pressure side will the concentration be \(0.5 \mathrm{~kg} / \mathrm{m}^{3}\) ? Assume a linear concentration profile.

Consider a diffusion couple composed of two cobalt-iron alloys; one has a composition of \(75 \mathrm{wt} \%\) Co-25 wt\% Fe; the other alloy composition is \(50 \mathrm{wt} \%\) Co-50 wt \(\% \mathrm{Fe}\). If this couple is heated to a temperature of \(800^{\circ} \mathrm{C}(1073 \mathrm{~K})\) for \(20,000 \mathrm{~s}\) determine how far from the original interface into the \(50 \mathrm{wt} \%\) Co-50 wt \% Fe alloy the composition has increased to \(52 \mathrm{wt} \%\) Co-48 wt Fe. For the diffusion coefficient, assume values of \(6.6 \times 10^{-t}\) \(\mathrm{m}^{2} / \mathrm{s}\) and \(247,000 \mathrm{~J} / \mathrm{mol}\), respectively, for the pre exponential and activation energy.

Briefly explain the concept of steady state as it applies to diffusion.

Self-diffusion involves the motion of atoms that are all of the same type; therefore, it is not subject to observation by compositional changes, as with interdiffusion. Suggest one way in which selfdiffusion may be monitored.

For the predeposition heat treatment of a semiconducting device, gallium atoms are to be diffused into silicon at a temperature of \(1150^{\circ} \mathrm{C}\) for \(2.5 \mathrm{~h}\). If the required concentration of \(\mathrm{Ga}\) at a position \(2 \mu \mathrm{m}\) below the surface is \(8 \times 10^{23}\) atoms \(/ \mathrm{m}^{3}\), compute the required surface concentration of \(\mathrm{Ga}\). Assume the following: (i) The surface concentration remains constant (ii) The background concentration is \(2 \times 10^{19} \mathrm{Ga}\) atoms \(/ \mathrm{m}^{3}\) (iii) Preexponential and activation energy values are \(3.74 \times 10^{-5} \mathrm{~m}^{2} / \mathrm{s}\) and \(3.39 \mathrm{eV} /\) atom, respectively.

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