Carbon diffuses in iron via an interstitial mechanism -for FCC iron from one octahedral site to an adjacent one. In Section \(4.3\) (Figure \(4.3 a\) ), we note that two general sets of point coordinates for this site are \(0 \frac{1}{2} 1\) and \(\frac{1}{2} \frac{1}{2} \frac{1}{2}\). Specify the family of crystallographic directions in which this diffusion of carbon in FCC iron takes place.

Short Answer

Expert verified
Based on the given points and the calculated vector, the family of crystallographic directions in which carbon diffuses from one octahedral site to an adjacent one in FCC iron is represented by [1𝑏110] or equivalently [𝑏110].

Step by step solution

01

Find the vector connecting the two points

To find the vector connecting the two points, we need to subtract the coordinates of the first point from those of the second point. So, let the two points be \(P(0, \frac{1}{2}, 1)\) and \(Q(\frac{1}{2}, \frac{1}{2}, \frac{1}{2})\). Then the PQ vector can be calculated as follows: PQ = Q - P = \((\frac{1}{2} - 0, \frac{1}{2} - \frac{1}{2}, \frac{1}{2} - 1) = (\frac{1}{2}, 0, -\frac{1}{2})\).
02

Determine the family of crystallographic directions

The PQ vector represents the direction between the points \(P\) and \(Q\). In order to represent the family of crystallographic directions, we need to obtain the shortest vector within the chosen coordinate system. We can do this by multiplying each component of the vector by the smallest common denominator, in this case 2. New PQ vector = \((\frac{1}{2}* 2, 0 * 2, -\frac{1}{2}* 2) = (1, 0, -1)\). This vector has the components 1, 0, and -1, which indicates the movement of one unit along the x-axis, 0 units along the y-axis, and -1 unit along the z-axis. But we are looking for the family of crystallographic directions, so we have to use angle brackets to represent the family [uvw]: \([100]\), \([010]\), and \([001]\) are the primary directions of motion. Since the diffusion happens in only the x- and z-axis, the family of crystallographic directions is \([1\bar{1}0]\) or equivalently \([\bar{1}10]\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interstitial Diffusion Mechanism
Diffusion is a critical process in materials science, involving the movement of atoms or molecules within a material. One of the key diffusion mechanisms is interstitial diffusion, which occurs when smaller atoms or ions move through the spaces between the larger atoms in a crystal lattice, referred to as interstitial sites. Unlike vacancy diffusion - which involves atoms exchanging places with vacancies in the lattice - interstitial diffusion does not require vacancies and can occur relatively easily due to the small size of the diffusing atoms.

This mechanism plays a significant role, particularly in alloys, where impurity atoms such as carbon in iron can diffuse efficiently. Interstitial diffusion is characterized by its high diffusion coefficients due to the lesser amount of energy needed for the atoms to move through the interstices compared to other mechanisms, like vacancy diffusion.
Octahedral Site Coordination
Within crystal lattices, there are various types of interstitial sites where atoms can reside. One common type is the octahedral site, which is surrounded by six atoms forming an octahedron. This coordination provides a geometric location where smaller atoms such as carbon can fit into the lattice of a larger atom matrix, like iron in the face-centered cubic (FCC) structure.

Octahedral sites are key to understanding diffusion in FCC structures because they provide pathways through which atoms can move. In the context of FCC iron, the octahedral interstices are the most common sites for carbon atoms, which are significantly smaller than iron atoms, allowing the interstitial diffusion mechanism to be an effective means of transport within the structure.
FCC Iron Carbon Diffusion
In the face-centered cubic (FCC) structure of iron, commonly known as austenite, carbon atoms diffuse through the octahedral interstices. The diffusion of carbon is essential in processes like steel hardening, where it impacts the mechanical properties of the material.

FCC iron consists of atoms at each corner and the center of each face of the cube, creating a dense arrangement with multiple octahedral sites. Carbon atoms, being smaller, can rapidly diffuse through these interstitial sites, essential for the formation of different iron-carbon phases and influencing the overall properties of steel. The control of carbon distribution within the iron lattice by diffusion directly affects the strength and ductility of the material.
Vector Determination for Crystallographic Directions
Understanding crystallographic directions requires determining the vector that represents movement within the crystal lattice. The vector originates from one lattice point and extends to another, representing the atomic movement direction. In the solution provided, we determined the vector connecting two octahedral interstitial sites in an FCC iron structure by subtracting the coordinates of the initial point from the final point.

To describe the family of equivalent crystallographic directions, angle brackets such as \\ are used. These directions are vital in describing slip directions, diffusion pathways, and many other crystallographic phenomena. In our diffusion example, the carbon atoms move along the \[1\bar{1}0\] direction in the FCC iron lattice, a direction combining vectors along the x- and z-axis, but not along the y-axis.

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Most popular questions from this chapter

Consider a diffusion couple between silver and a gold alloy that contains 10 wt \% silver. This couple is heat treated at an elevated temperature and it was found that after 850 s, the concentration of silver had increased to \(12 \mathrm{wt} \%\) at \(10 \mu \mathrm{m}\) from the interface into the Ag-Au alloy. Assuming preexponential and activation energy values of \(7.2 \times 10^{-6}\) \(\mathrm{m}^{2} / \mathrm{s}\) and \(168,000 \mathrm{~J} / \mathrm{mol}\), respectively, compute the temperature of this heat treatment. (Note: You may find Figure \(5.13\) and Equation \(5.15\) helpful.) For a steel alloy, it has been determined that a carburizing heat treatment of \(15 \mathrm{~h}\) duration will raise the carbon concentration to \(0.35\) wt \(\%\) at a point \(2.0 \mathrm{~mm}\) from the surface. Estimate the time necessary to achieve the same concentration at a \(6.0-\mathrm{mm}\) position for an identical steel and at the same carburizing temperature.

Consider a diffusion couple composed of two cobalt-iron alloys; one has a composition of \(75 \mathrm{wt} \%\) Co-25 wt\% Fe; the other alloy composition is \(50 \mathrm{wt} \%\) Co-50 wt \(\% \mathrm{Fe}\). If this couple is heated to a temperature of \(800^{\circ} \mathrm{C}(1073 \mathrm{~K})\) for \(20,000 \mathrm{~s}\) determine how far from the original interface into the \(50 \mathrm{wt} \%\) Co-50 wt \% Fe alloy the composition has increased to \(52 \mathrm{wt} \%\) Co-48 wt Fe. For the diffusion coefficient, assume values of \(6.6 \times 10^{-t}\) \(\mathrm{m}^{2} / \mathrm{s}\) and \(247,000 \mathrm{~J} / \mathrm{mol}\), respectively, for the pre exponential and activation energy.

A sheet of BCC iron \(2-\mathrm{mm}\) thick was exposed to a carburizing gas atmosphere on one side and a decarburizing atmosphere on the other side at \(675^{\circ} \mathrm{C}\). After reaching steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces of the sheet were determined to be \(0.015\) and \(0.0068\) wt \(\%\), respectively. Compute the diffusion coefficient ifthe diffusion flux is \(7.36 \times 10^{-9} \mathrm{~kg} / \mathrm{m}^{2}+\mathrm{s}\). Hint: Use Equation \(4.9\) to convert the concentrations from weight percent to kilograms of carbon per cubic meter of iron.

Briefly explain the difference between selfdiffusion and interdiffusion.

The steady-state diffusion flux through a metal plate is \(7.8 \times 10^{-8} \mathrm{~kg} / \mathrm{m}^{2} \cdot \mathrm{s}\) at a temperature of \(1200^{\circ} \mathrm{C}(1473 \mathrm{~K})\) and when the concentration gradient is \(-500 \mathrm{~kg} / \mathrm{m}^{4}\). Calculate the diffusion flux at \(1000^{\circ} \mathrm{C}(1273 \mathrm{~K})\) for the same concentration gradient and assuming an activation energy for diffusion of \(145,000 \mathrm{~J} / \mathrm{mol}\).

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