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Chapter 6: Problem 32

(a) What is the approximate ductility (\%EL) of a brass that has a yield strength of \(345 \mathrm{MPa}\). \((50,000 \mathrm{psi}) ?\) (b) What is the approximate Brinell hardness of a 1040 steel having a yield strength of 620 MPa \((90,000\) psi)?

Short Answer

Expert verified
Question: Calculate the ductility (%EL) of a brass material with a yield strength of 345 MPa, and the Brinell hardness (HB) of a 1040 steel with a yield strength of 620 MPa. Answer: The ductility of the brass material is approximately 40.44%, and the Brinell hardness of the 1040 steel is 620.

Step by step solution

01

Part (a): Calculate the ductility (%EL) of a brass material

First, convert the given yield strength from MPa to GPa by dividing it by 1000: \(G = \frac{345 \mathrm{MPa}}{1000} = 0.345 \mathrm{GPa}\) Next, plug the value of G into the formula for %EL for brass: %EL = \(57 - 48(0.345)\) %EL = \(57 - 16.56\) %EL = \(40.44\) Therefore, the approximate ductility of the brass material is 40.44%.
02

Part (b): Calculate the Brinell hardness (HB) of a 1040 steel

Since 1040 steel is a medium-carbon steel, we can assume that the k value is 1. Now, we can plug in the yield strength (σy) into the formula for Brinell hardness (HB): HB = \(1(620)\) HB = \(620\) Therefore, the approximate Brinell hardness of the 1040 steel is 620.

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Most popular questions from this chapter

A cylindrical specimen of steel having a diameter of \(15.2 \mathrm{~mm}(0.60 \mathrm{in} .)\) and length of 250 \(\mathrm{mm}(10.0 \mathrm{in} .)\) is deformed elastically in tension with a force of \(48,900 \mathrm{~N}\left(11,000 \mathrm{lb}_{\mathrm{f}}\right)\). Using the data contained in Table \(6.1\), determine the following: (a) The amount by which this specimen will elongate in the direction of the applied stress. (b) The change in diameter of the specimen. Will the diameter increase or decrease?

A specimen of copper having a rectangular cross section \(15.2 \mathrm{~mm} \times 19.1 \mathrm{~mm}(0.60 \mathrm{in} . \times 0.75 \mathrm{in}\).) is pulled in tension with \(44,500 \mathrm{~N}\left(10,000 \mathrm{lb}_{\mathrm{f}}\right)\) force, producing only elastic deformation. Calculate the resulting strain.

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A non-cold-worked brass specimen of average grain size \(0.01 \mathrm{~mm}\) has a yield strength of \(150 \mathrm{MPa}\) (21,750 psi). Estimate the yield strength of this alloy after it has been heated to \(500^{\circ} \mathrm{C}\) for \(1000 \mathrm{~s}\), if it is known that the value of \(\sigma_{0}\) is 25 MPa (3625 psi).

Briefly explain why HCP metals are typically more brittle than \(\mathrm{FCC}\) and \(\mathrm{BCC}\) metals.
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