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Chapter 8: Problem 37

A cylindrical component constructed from an S-590 alloy (Figure 8.31) has a diameter of \(14.5 \mathrm{~mm}\) (0.57 in.). Determine the maximum load that may be applied for it to survive \(10 \mathrm{~h}\) at \(925^{\circ} \mathrm{C}\left(1700^{\circ} \mathrm{F}\right)\).

Short Answer

Expert verified
Answer: To determine the maximum load, follow these steps: 1. Find the creep strength at 925°C and 10 hours using the S-590 alloy's table or graph. 2. Calculate the cross-sectional area of the cylindrical component using the formula A = πd²/4. 3. Use the stress formula (σ = F/A) to find the maximum load by rearranging it as F = σ * A, and calculate the result based on the creep strength and cross-sectional area values.

Step by step solution

01

Find the creep strength at the given temperature and time

Refer to the provided S-590 alloy figure (Figure 8.31). For the given temperature of 925°C and a time of 10 hours, you should be able to find the creep strength (\(\sigma\)) using the table or graph. Note that the time must be converted to hours if necessary.
02

Find the cross-sectional area of the cylindrical component

As mentioned, the diameter of the cylindrical component is \(14.5\mathrm{~mm}\) (0.57 in.). To find the cross-sectional area (A), use the formula for the area of a circle: \[ A = \frac{\pi d^2}{4} \] where \(d\) is the diameter. Plug in the given diameter and calculate the cross-sectional area.
03

Calculate the maximum load

Now that you have the creep strength (\(\sigma\)) and the cross-sectional area (A), use the stress formula to calculate the maximum load (F): \[ \sigma = \frac{F}{A} \] Rearrange to find the maximum load: \[ F = \sigma \cdot A \] Plug in the creep strength and cross-sectional area, and calculate the maximum load that can be applied on the cylindrical component for it to survive 10 hours at 925°C. After completing these steps, you will have determined the maximum load that can be applied on the S-590 alloy cylindrical component for the given conditions.

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Most popular questions from this chapter

Cite three metallurgical/processing techniques that are employed to enhance the creep resistance of metal alloys.

The following creep data were taken on an aluminum alloy at \(480^{\circ} \mathrm{C}\left(900^{\circ} \mathrm{F}\right)\) and a constant stress of \(2.75 \mathrm{MPa}\) (400 psi). Plot the data as strain versus time, then determine the steady-state or minimum creep rate. Note: The initial and instantaneous strain is not included. $$ \begin{array}{cccc} \hline \text { Time } \text { (min) } & \text { Strain } & \text { Time } \text { (min) } & \text { Strain } \\ \hline 0 & 0.00 & 18 & 0.82 \\ \hline 2 & 0.22 & 20 & 0.88 \\ \hline 4 & 0.34 & 22 & 0.95 \\ \hline 6 & 0.41 & 24 & 1.03 \\ \hline 8 & 0.48 & 26 & 1.12 \\ \hline 10 & 0.55 & 28 & 1.22 \\ \hline 12 & 0.62 & 30 & 1.36 \\ \hline 14 & 0.68 & 32 & 1.53 \\ \hline 16 & 0.75 & 34 & 1.77 \\ \hline \end{array} $$

A structural component is fabricated from an alloy that has a plane-strain fracture toughness of \(62 \mathrm{MPa} \sqrt{\mathrm{m}}\). It has been determined that this component fails at a stress of \(250 \mathrm{MPa}\) when the maximum length of a surface crack is \(1.6 \mathrm{~mm}\). What is the maximum allowable surface crack length (in mm) without fracture for this same component exposed to a stress of \(250 \mathrm{MPa}\) and made from another alloy with a plane-strain fracture toughness of \(51 \mathrm{MPa} \sqrt{\mathrm{m}}\) ?

(a) Using Figure 8.31, compute the rupture lifetime for an \(S-590\) alloy that is exposed to a tensile stress of \(400 \mathrm{MPa}\) at \(815^{\circ} \mathrm{C}\). (b) Compare this value to the one determined from the Larson-Miller plot of Figure \(8.33\), which is for this same S-590 alloy.

A cylindrical component constructed from an S-590 alloy (Figure 8.31) is to be exposed to a tensile load of \(20,000 \mathrm{~N}\). What minimum diameter is required for it to have a rupture lifetime of at least \(100 \mathrm{~h}\) at \(925^{\circ} \mathrm{C} ?\)
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