Change the independent variable to simplify the Euler equation, and then find a first integral of it.

3.x1x2xt2xt2+x2dy

Short Answer

Expert verified

Answer

The equation x4y'2=C21+x2y'23can be left in this form, since the solution is not trivial and there is no need to solve it.

Step by step solution

01

Given Information

The given integral isx1x2x'2x'2+x2dy.

02

Definition of Euler equation

For the integrall(ε)=x1x2(x,y,y)dx, the Euler equation is mathematically presented as ddxdFdy'-dFdy=0.

03

Find the Euler equation of the given function

The given integral is x4y'2=C21+x2y'23.

First, let’s change the variables as follows:

dx=x'dyy'=1x'

By using the two equations above, we can rewrite the integral.

x'2x'2+x2dy=x'2x'2+x2dxx'=y'-2y'-2+x2y'dx=1y'y'-2+x2dx=11+y'2x2dx

Let Fx,y,y'=11+y'2x2

By the definition of the Euler equation,ddxFF-Fy=0.

Differentiate F with respect to y' and y.

Fy'=y'x21+x2y'232Fy=0

The Euler equations becomes:

ddxy'x21+x2y'232=0y'x21+x2y'232=Cx4y'31+x2y'23

We shall leave the equationx4y'31+x2y'23in this form, since the solution is not trivial and there is no need to solve it.

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