Follow steps (a), (b), (c) above to find all the values of the indicated roots $\sqrt{\mathbf{i}}$.

The given expression is$\sqrt{i}$.

Complex numbers have both real numbers and imaginary numbers in them; a complex can be written in the form of:

z=a+ib

Here a and b are real numbers, and i is the imaginary number which is known as iota, whose value is$\sqrt{\mathbf{-}\mathbf{1}}$

The Complex number is in the form 0+i .

x=0,y=1

The polar coordinates of the point are in the form of $z=r{e}^{i\theta }$ .

$$\begin{gathered} r=1 \\ \theta =\frac{\pi }{2},or\frac{5\pi }{2},\frac{9\pi }{2},.... \end{gathered}$$

The equation $z=r{e}^{i\theta }$can also be written in another form.

role="math" localid="1658744103977" $$\begin{gathered} z^{\frac{1}{n}}={\left(r{e}^{i\theta }\right)}^{\frac{1}{n}} \\ {z}^{\frac{1}{n}}=r^{\frac{1}{n}}{e}^{\frac{i\theta }{n}} \\ {z}^{\frac{1}{n}}=\sqrt[n]{r}\left(\cos \frac{\theta }{n}+i\sin \frac{\theta }{n}\right)\left(1\right) \end{gathered}$$

When n=2, the equation becomes the 2nd root of the complex number.

$$\begin{gathered} z^{\frac{1}{2}}=r^{\frac{1}{2}}{e}^{\frac{i\theta }{2}} \\ \theta =\frac{\pi }{4},\frac{5\pi }{4},\frac{9\pi }{4},......... \end{gathered}$$

It is clear from the above graph that the points $\left(1,\frac{\pi }{4}\right)$and the point$\left(1,\frac{9\pi }{4}\right)$ are the same.

The radius of the circle is 1 and equally spaced $\pi$apart.

$$\begin{gathered} r=1 \\ \theta =\frac{\pi }{4},\frac{5\pi }{4} \end{gathered}$$

Hence, the value of$\sqrt{i}=\frac{\pm \left(1+i\right)}{\sqrt{2}}$