Find one or more values of each of the following complex expressions and compare with a computer solution.

(1+i1-i)2718

Short Answer

Expert verified

The value of the complex number is,z=-1 .

Step by step solution

01

Given Information.

The given expression is,(1+i1-i)2718 .

02

Definition of complex series.

The numbers that are presented in the form ofa+ib where, a is real numbers and ' ib ' is an imaginary number called complex numbers.

Example:3+2i .

03

Convert into polar form.

Consider.

z1=1+iz2=1-i

Write both in polar form.

z1=1+iz1=2eπi/4z2=1-iz2=2e-πi/4

04

Substitute the values and solve.

Put both the value in the given question.

z=1+i1-i2718z=2eπi/42e-πi/42718z=eπi/42718z=e1359πi

z=cos(1359π)+isin(1359π)z=cos(1359π-2)+isin(1359π-2)z=cos(1359π-1358π)+isin(1359π-1358π)z=cosπ+isinπ

z=-1

Hence the value is found to be1+i1-i2718=-1

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