Repeat Problem 11:

(a) Ifq=Re4e30iπt

(b) Ifq=lm4e30iπt

Short Answer

Expert verified

a)

  1. The velocity amplitude is 120πi.
  2. Amplitude = 4
  3. Period=115
  4. Frequency = 15

b)

  1. The velocity amplitude is 120πi.
  2. Amplitude = 4
  3. role="math" localid="1659244633384" Period=115
  4. Frequency = 15

Step by step solution

01

Given data

The given function is q=Re4e30iπtand q=4cos30iπt.

02

Concept of Periodic motion formula

Time Period (T): The length of time it takes for a motion to repeat itself. Thus, a time period is measured in seconds.

Frequency (f): It is determined by counting how many times a motion is repeated in a second. Hz is the symbol for frequency (Hertz).

Frequency is related to Time period as f=1T.

03

Calculation of the real function q=Re4e30iπt 

Consider a particle whose coordinate is Re(z).

Now, Req=q=4cos30iπt.

By definition an object is executing simple harmonic motion if its displacement from equilibrium can be written as:

role="math" localid="1659245878662" Asinωt[OrAcosωt orAsinωt-ϕ or Acosωt-ϕ].

Hence, this particle is undergoing simple harmonic motion.

Now, Req=q=4cos30iπt.

Amplitude = 4

ω=30i

Period=2πωPeriod=2π30πPeriod=115

Frequency=1PeriodFrequency=15

Velocity amplitude=Aω

Velocity amplitude =120πi

04

Calculation of the imaginary function q=lm4e30iττt

Consider a particle whose coordinate is lm(z).

Now, lmq=q=4sin30iπt.

By definition an object is executing simple harmonic motion if its displacement from equilibrium can be written as:

Asinωt[OrAcosωtorAsinωt-ϕorAcosωt-ϕ]

Hence, this particle is undergoing simple harmonic motion.

Now, lmq=q=4sin30iπt.

Amplitude = 4

ω=30πi

Period=2πω

Period=2π30πi

Period=115i

Frequency=1Period

Frequency=15i

Velocity amplitude =Aω

Velocity amplitude =120πi.

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Most popular questions from this chapter

Use a computer to produce graphs like Fig. 6.2 showing Fourier series approximations to the functions in Problems 5.1 to 5.3, and 5.7 to 5.11. You might like to set up a computer animation showing the Gibbs phenomenon as the number of terms increases.

In each of the following problems you are given a function on the interval -π<x<π .Sketch several periods of the corresponding periodic function of period . Expand the periodic function in a sine-cosine Fourier series,

f(x)={0,-π<x<0x,0<x<π

The displacement (from equilibrium) of a particle executing simple harmonic motion may be eithery=Asinωtory=Asin(ωt+ϕ)depending on our choice of time origin. Show that the average of the kinetic energy of a particle of mass m(over a period of the motion) is the same for the two formulas (as it must be since both describe the same physical motion). Find the average value of the kinetic energy for thesin(ωt+ϕ)case in two ways:

(a) By selecting the integration limits (as you may by Problem 4.1) so that a change of variable reduces the integral to thecase.

(b) By expandingsin(ωt+ϕ)by the trigonometric addition formulas and using (5.2) to write the average values.

Sketch several periods of the corresponding periodic function of period 2π. Expand the periodic function in a sine-cosine Fourier series.

f(x)=0,-π<x<01,0<x<π2,0,π2<x<π.

Use Parseval’s Theorem and the results of the indicated problems to find the sum of the series in Problems 5to 9

The series 132+1152+1352+..., using Problem 5.11

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