Find the real and imaginary parts $\mathit{u}\left(x,y\right)$ and$\mathit{v}\left(x,y\right)$ of the following functions.

$\sqrt{\mathbf{z}}$

Complex numbersare expressed in the form of $\mathit{z}\mathbf{}\mathbf{=}\mathbf{}\mathit{x}\mathbf{}\mathbf{+}\mathbf{}\mathit{i}\mathit{y}$, where x,y are real numbers, and i is an imaginary number.

Similarly, the function of z is represented as follows:

$\mathit{f}\left(z\right)\mathbf{=}\mathit{f}\left(x+iy\right)\mathbf{=}\mathit{u}\left(x,y\right)\mathbf{+}\mathit{i}\mathit{v}\left(x,y\right)$, where $\mathit{u}\left(x,y\right)$is the real part and$\mathit{v}\left(x,y\right)$ is the imaginary part.

Polar form of complex number is represented as:

$\mathit{x}\mathbf{}\mathbf{+}\mathbf{}\mathit{i}\mathit{y}\mathbf{}\mathbf{=}\mathit{r}{\mathit{e}}^{\mathbf{i}\mathbf{\theta }}$,where$\mathit{r}\mathbf{}\mathbf{=}\mathbf{}\sqrt{{\mathbf{x}}^{\mathbf{2}}\mathbf{+}{\mathbf{y}}^{\mathbf{2}}}$,$\mathit{\theta }\mathbf{=}{\mathbf{tan}}^{\mathbf{-}\mathbf{1}}\left(\frac{y}{x}\right)$

Given the function is$\sqrt{z}$ .

The complex number z can be written as:

$z=x+iy$, where x is a real part and y is an imaginary part.

Substitute the complex number and simplify.

$$\begin{gathered} \sqrt{z}={\left(x+iy\right)}^{\frac{1}{2}} \\ ={\left(r{e}^{i\theta }\right)}^{\frac{1}{2}} \end{gathered}$$

$$\begin{gathered} \sqrt{z}={\left(r{e}^{i\theta }\right)}^{\frac{1}{2}} \\ =r^{\frac{1}{2}}{e}^{\frac{i\theta }{2}} \\ =r^{\frac{1}{2}}\left(\cos \left(\frac{\theta }{2}\right)+i\sin \left(\frac{\theta }{2}\right)\right)----\left(1\right) \end{gathered}$$

where$r=\sqrt{x^2+y^2}$ and$\theta ={\tan }^{-1}\left(\frac{y}{x}\right)$

Simplify the equationfurther.

$$\begin{gathered} \sqrt{z}=r^{\frac{1}{2}}\left(\cos \left(\frac{\theta }{2}\right)+i\sin \left(\frac{\theta }{2}\right)\right) \\ ={\left[{\left(x^2+y^2\right)}^{\frac{1}{2}}\right]}^{\frac{1}{2}}\left(\cos \left(\frac{\theta }{2}\right)+i\sin \left(\frac{\theta }{2}\right)\right) \\ ={\left(x^2+y^2\right)}^{\frac{1}{4}}\left(\cos \left(\frac{\theta }{2}\right)+i\sin \left(\frac{\theta }{2}\right)\right) \\ ={\left(x^2+y^2\right)}^{\frac{1}{4}}\cos \left(\frac{\theta }{2}\right)+i{\left(x^2+y^2\right)}^{\frac{1}{4}}\sin \left(\frac{\theta }{2}\right) \end{gathered}$$

Hence, the real part is${\left(x^2+y^2\right)}^{\frac{1}{4}}\cos \left(\frac{\theta }{2}\right)$ and imaginary part is $i{\left(x^2+y^2\right)}^{\frac{1}{4}}\sin \left(\frac{\theta }{2}\right)$, where$\theta ={\tan }^{-1}\left(\frac{y}{x}\right)$ .