Chapter 1: Q.10.10P (page 22)

$\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n} x^{2 n}}{{(2 n)}^{\frac{3}{2}}}$

Short Answer

Expert verified

The interval of convergence is $[- 1, 1]$

Step by step solution

Given Information

The power series is $\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n} x^{2 n}}{{(2 n)}^{\frac{3}{2}}}$

Definition of the interval of convergence.

The Interval of convergence is the interval in which the power series is convergent.

Find the interval

The power series is $\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n} x^{2 n}}{{(2 n)}^{\frac{3}{2}}}$

Let $ρ_{n} = |\frac{a_{n + 1}}{a_{n}}|$ ,

Substitute the value of the power series in the formula above, the equation becomes as follows,

$ρ_{n} = |\frac{a_{n + 1}}{a_{n}}|$

= \frac{\frac{x^{2 n + 2}}{{(2 n + 2)}^{\frac{3}{2}}}}{\frac{x^{2 n}}{{(2 n)}^{\frac{3}{2}}}}

$= |\frac{x^{2 n + 2} {(2 n)}^{\frac{3}{2}}}{x^{2 n} {(2 n + 2)}^{\frac{1}{2}}}|$

$= |\frac{x^{2} 2^{\frac{3}{2}}}{{(2 + \frac{2}{n})}^{\frac{3}{2}}}|$

Apply limits in the above equation,

$ρ = \lim_{n \to \infty} |\frac{x^{2} 2^{\frac{3}{2}}}{{(2 + \frac{2}{n})}^{\frac{3}{2}}}|$

= |x^{2}|

The power series is convergent for $ρ < 1$ ,

Hence the given power series is convergent for $|x^{2}| < 1$ and divergent for $|x^{2}| > 1$ .

Now check the ends points,

When $x = 1$ series is $\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n}}{n^{\frac{3}{2}}}$ , which is a convergent alternating series.

When $x = - 1$ series is $\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n}}{n^{\frac{3}{2}}}$ , which is a convergent alternating series.

Hence the interval of convergence is $[- 1, 1]$ .

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$\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n} x^{2 n}}{{(2 n)}^{\frac{3}{2}}}$

Short Answer

Step by step solution

Given Information

Definition of the interval of convergence.

Find the interval

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∑n=1∞(-1)nx2n(2n)32

Short Answer

Step by step solution

Given Information

Definition of the interval of convergence.

Find the interval

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Scientific Method Physics

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Mechanics and Materials

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Study anywhere. Anytime. Across all devices.

$\sum_{n = 1}^{\infty} \frac{{(- 1)}^{n} x^{2 n}}{{(2 n)}^{\frac{3}{2}}}$