In a water purification process, one-nth of the impurity is removed in the first stage. In each succeeding stage, the amount of impurity removed is one-nth of that removed in the preceding stage. Show that ifn=2, the water can be made as pure as you like, but thatn=2 if, at least one-half of the impurity will remain no matter how many stages are used.

Short Answer

Expert verified

After an infinite number of purification processes withn=2, the percentage of impurity eliminated is100% of the time

After an infinite number of purification processes with n=3, the percentage of impurity eliminated is 50%of the time.

Step by step solution

01

Explanation of solution

Provided Information:

One-nth of the contaminant is eliminated in the first step of a water purification procedure. Each succeeding stage removes one-tenth of the impurity that was eliminated in the preceding stage.

02

Geometric series

The expression for sum of infinite GP series.

S=a1-r

Where, S is the sum of GP up to infinite terms.

03

Calculation

Another geometric series-described method is water purification, as explained here. If each stage of purification removes one-nth of the current impurity, the total proportion of the impurity removed after N stages is given by

Impurity(n,N)=1n+1n2+....+1nN=1n1-1nN1-1nN=1nNnN-1n-1.

Therefore, for the two scenarios above, n=2and n=3, we'll look into the limNto determine what fraction of the impurity we can remove in an infinite number of steps.

First scenario: n=2

limNImpurity2,N=limN12N2N-12-1limN2N2N=1

Second scenario: n=3

limNImpurity3,N=limN13N3N-13-1limN3N3N12=12

Thus, in the first scenario, we can eradicate all of the impurity; however, in the second scenario, with only a third removed at each stage, we can only hope to remove one half of the impurity.

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