By computer or tables, find the exact sum of each of the following series.

(a)n=1n(4n2-1)2(b)n=1n3n!(c)n=1n(n+1)3n

Short Answer

Expert verified
  1. The sum of the seriesn=1n(4n2-1)2=18.
  2. The sum of the seriesn=1n3n!=13.5914091422=5e.
  3. The sum of the series n=1n(n+1)3n=94.

Step by step solution

01

Given Information

The given series are, i.e.,

(a)n=1n(4n2-1)2(b)n=1n3n!(c)n=1n(n+1)3n

02

Definition of Sum of a Series

The total of all the terms in a sequence can be solved as the sum of a series.

03

(a) Find the exact sum of the series ∑n=1∞n(4n2-1)2

Use the MATLAB tool to calculate the exact sum of the series,

Hence, the sum of the series n=1n(4n2-1)2=18.

04

(b) Find the exact sum of the series ∑n=1∞n3n!

Use the MATLAB tool to calculate the exact sum of the series,

Hence, the sum of the series n=1n3n!=13.5914091422=5e.

05

(c) Find the exact sum of the series ∑n=1∞n(n+1)3n

Use the MATLAB tool to calculate the exact sum of the series n=1n(n+1)3n,

Hence, the sum of the series n=1n(n+1)3n=94.

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