Use Maclaurin to do problem 26 to 29 and check your results by computer.

d6dx6(x4ex2)x=0

Short Answer

Expert verified

Answer using Maclaurin series is

d6dx6(x4ex2)x=0=720

Step by step solution

01

Maclaurin series and given information:

Consider .d6dx6(x4ex2)x=0

Maclaurin series:f(x)=f(0)+f'(0)1!(x)+f''(0)2!(x2)+

02

Use the Maclaurin series:

Letfx=x4ex2

Consider the expansion of ex.

ex=1+x+x22!+x33!+ex2)=1+x2+x42!+x63!+.x4ex2)=x4+x6+x82!+x103!+....

Therefore,

f(x)=x4e(x2)=x4+x6+x82!+x103!+

Find the derivatives of f(x) at x=0 .

f'(x)=4x3+6x5+.f''(x)=12x2+30x4+....d6dx6f(x)x=0=720

Hence,d6dx6f(x)x=0=720

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