1-x1+x

Short Answer

Expert verified

1-x1+x=1-x+x22-x32+

Step by step solution

01

Given information

The Maclaurin expansion of the function1-x1+x is to be evaluated.

02

Definition of Maclaurin series

The definition of the Maclaurin series is defined.

(1-x)1/2=1-x2-x28-x316+


(1+x)-1/2=1-x2+3x28-5x316+

03

Part-A  Step 3: Begin by stating the Maclaurin series

State the Maclaurin series.

(1-x)1/2=1-x2-x28-x316+

(1+x)-1/2=1-x2+3x28-5x316+

04

Part-B Step 3: Use both Maclaurin series to evaluate

Use both Maclaurin series to evaluate.

1-x1+x=(1-x)1/2×(1+x)-1/2

=1-x2-x28-x316+×1-x2+3x28-5x316+

1-x1+x=1+-256x+128x2-128x3+256

1-x1+x=1-x+x22-x32+

Thus, the final answer is1-x1+x=1-x+x22-x32+

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