Find the general solution of(1.2)for an RLcircuit(1C=0)withV=Vcosωt(ω=constant).

Short Answer

Expert verified

I=Vω2L2+R2ωLsinωt+Rcosωt+αe-Rt/L

Step by step solution

01

Define the First-order differential equation

The linear differential equation is defined byx'+Px=Q, whereP and Qare numeric constants or functions in x. It is made up of a yand a yderivative. The differential equation is called the first-order linear differential equation because it is a first-order differentiation.

02

Given parameter

Given equation 1.2:

LdIdt+RI+qC=V

Also given RI circuit1C=0 withV=V0cosωtω=constant

03

Find the differential equation and write it in the formx'+Px=Q

From V=V0cosωtω=constant, the equation 1.2 will become

LdIdt+RI=V0cosωt

Then the equation in the form will be

dIdt+RLI=V0Lcosωt

From the equation 3.4,

f=RLdt=RLtef=eRtL

04

 Find the general solution of the differential equation

From the equation 3.9,

lef=∫VLcosωteRt/Ldt=VLe-Rt/Lω2+R/L2ωsinωt+RLcosωt+αI=Vω2L2+R2ωLsinωt+Rcosωt+αe-Rt/L

So, the general solution will be:

I=Vω2L2R2ωLsinωt+Rcosωt+αe-Rt/L

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