Use L32 and L3 to obtain L11

L{tsinat}=2ap(p2+a2)2

Short Answer

Expert verified

Answer

The solution isL{tsinat}=2ap(p2+a2)2. So, given function is proved.

Step by step solution

01

Given information

The given function is L{tsinat}=2ap(p2+a2)2

02

Definition of Laplace Transformation

A transformation of a function f(x) into the function g(t) that is useful especially in reducing the solution of an ordinary linear differential equation with constant coefficients to the solution of a polynomial equation.

The inverse Laplace transform of a function F(s) is the piecewise-continuous and exponentially-restricted real function f(t)

03

Properties used to prove a given function

L32:L{tngt}=-1xd4GpdrnL3:Lsinat=wp2+a2

04

Convert L32 and L3 into L11

Now, consider the LaplaceLxsinat.

role="math" localid="1654145096715" Ltπgt=-1ndnGpdpnLt1sinat=-11ddpap2+a2

Differentiate with quotient rule, ddxfz=Tg-fgng2

Lt1sinat=-ddpap2+a2Ltsinat=-0p2+a2-ppap2+a22Ltsinat=--2app2+a22Ltsinat=2app2+a22

Hence Ltsinat=2app2+a22

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