Solve the equation for the rate of growth of bacteria if the rate of increase is proportional to the number present but the population is being reduced at a constant rate by the removal of bacteria for experimental purposes

Short Answer

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Answer

The rate of growth of bacteria N is Nt=N0ekt-RKekt-1.

Step by step solution

01

Given information

It is given that the rate of increase is proportional to the number present, but the population is being reduced at a constant rate by removing bacteria for experimental purposes.

02

Definition of differential equation

A differential equation contains at least onederivative of an unknown function, either an ordinary derivative or a partial derivative.

03

Find N as a function of t

It is given that the rate of increase is proportional to the number present, but the population is being reduced at a constant rate by removing bacteria for experimental purposes.

Let removal rate = R

Therefore,

dNdt=KN-RdNKN-R=dtbnKN-RK=t+Nt=α2eKt+RK.

Here, α2=eαk.

Now, at t=0,N=N0

N0=N0=α2+RKα2=N0K-R

Thus,

Nt=N0ekt-RKekt-1.

Therefore, the number N of bacteria as a function of time t is Nt=N0ekt-RKekt-1.

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