Heat is escaping at a constant rate [dQdtin (1.1)is constant] through the walls of a long cylindrical pipe. Find the temperature T at a distance r from the axis of the cylinder if the inside wall has radius r=1and temperature T=100and the outside wall has r=2and T=0

Short Answer

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Answer

The temperature T at a distance r from the axis of the cylinder is T=1001-InrIn2

Step by step solution

01

Given information

It is given that the heat is escaping at a constant ratedQdt through the walls of a long cylindrical pipe.

02

Definition of differential equation

A differential equation contains at least onederivative of an unknown function, either an ordinary derivative or a partial derivative.

03

Find temperature 

It is given that the heat is escaping at a constant rate dQdtthrough the walls of a long cylindrical pipe.

Therefore,

dQdt=KAdTdrQKA=dTdr∫Q0KAdr=∫dT,

Since dQdtis constant , dQdtis replaced with Q0above.

The pipe is very long, so the area of the circles at the top and bottom is ignored.

Thus, πArh=2.

Therefore,

Q0π2hk∫rdr=∫dTQ0π2hkhr=T+.

Use the boundary conditions of the inside and outside cylinder to find two arbitrary constants Q0and α

Now, inside the cylinder, r=1and T=100.

Q0π2hKh1=100+⇒α=-100

Now, outside the cylinder, r=2and T=0.

Q0π2hKIn2=0-100⇒Q0=πhK200In2

Put the values of Q0and αinto the general solution Q0π2hKInr=T+

Thus, T=1001-InrIn2.

Therefore, the temperature T at a distance r from the axis of the cylinder is T=1001-InrIn2

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