Solve Laplace transforms and the convolution integral or by Green functions.

y''+y=sec2t

Short Answer

Expert verified

The general solution of the equation y''+y=sec2tisyt=Asint+Bcos(t)+sin(t)In(sec(t)+tan(t))-1

Step by step solution

01

Given Information

The given expressions arey''+y=sec2t

02

Green Function

The impulse response of an inhomogeneous linear differential operator defined on a domain with specified initial conditions or boundary conditions is known as a Green's function.

03

Green Function

Use the green function, where the given differential equation have the following form

y''+ω2y=ft...2

Compare equation (1) and (2)

ω=1ft=1cost2

And, the solution to such differential equation is,

ytp=1ω0tsinωt-t'ft'dt

Hence, the solution is thus,

ytp=1ω0tsint-t'sect'2dt'

04

The general solution of the equation

The sec function is

sect2=1cos(t)2

And, use double angle identity that

α=0β=1

Thus,

yt=e0Asint+Bcost=Asint+Bcost

And, hence the general solution to the differential equation, is thus

yt=ytc=ytp

And, thus

yt=Asint+Bcost+sintInsect+tan(t)+cost-1

B=B+1

Thus,

y(t)=Asin(t)+(B+1)cos(t)+sin(t)In(sec(t)+tan(t))+cos(t)-1n&y(t)=Asin(t)+Bcos(t)+sin(t)In(sec(t)+tan(t))-1

Hence, the general solution of the y''+y=sec2t

y(t)=Asin(t)+Bcos(t)+sin(t)In(sec(t)+tan(t))-1

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