Find the position x of a particle at time t if its acceleration isd2xdt2=Atωsin.

Short Answer

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Answer

The position x of a particle at time t is xω=-Aωt-2sin+ct+dwhen acceleration is d2xdt2=Atωsin.

Step by step solution

01

Given information

In this question, the acceleration is given as d2xdt2=Atωsin

02

Meaning of differential equation

In mathematics, an equation with only one independent variable and one or more of its derivatives with respect to the variable is referred to as an ordinary differential equation or ODE. In other words, the ODE is a relation with one independent variable x, a real dependent variable y, and several derivatives y',y",....,ynin relation to x.

03

Find the position of a particle

The given acceleration is d2xdt2=Atωsin.

Integrate the acceleration two times.

dxdt=Atωsindt=-Aω-1cosωt+c

The second integration will be

dx=-Aωt-1cos+dtdx=-Atωdt-1cosdt+xω=-Aωt-2sin+ct+d

Therefore, the position of a particle at time t is xω=-Aωt-2sin+ct+d.

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