Given a non uniform sample space and the probabilities associated with the points, we defined the probability of an event A as the sum of the probabilities associated with the sample points favorable to A. [You used this definition in Problem 15with the sample space (2.5).] Show that this definition is consistent with the definition by equally likely cases if there is also a uniform sample space for the problem (as there was in Problem 15). Hint: Let the uniform sample space have n<Npoints each with the probability N-1. Let the nonuniform sample space have n points, the first point corresponding to N1 points of the uniform space, the second to N2 points, etc. What is N1 + N2 + .... Nn ?What are p1, p2, ...the probabilities associated with the first, second, etc., points of the nonuniform space? What is p1 + p2 +....+ pn? Now consider an event for which several points, say i, j, k, of the nonuniform sample space are favorable. Then using the nonuniform sample space, we have, by definition of the probability p of the event, p = pi + pj + pk . Write this in terms of the N’s and show that the result is the same as that obtained by equally likely cases using the uniform space. Refer to Problem 15as a specific example if you need to.

Short Answer

Expert verified

The values are mentioned below:

p(A) = (n/N)

p(R) = 3/N

Step by step solution

01

Given Information

Non-uniform sample space and the probability associated with the points.

02

Definition of Probability

Probability is a metric for determining the possibility of an event occurring.

03

Prove the statement.

Set S contains N points with equally likely probability,

S = {N1, N2, N3, ..... NN}

Let A be the event where set A is the part of the mother set S,

A = {N1, N2, N3, ..... Nn}

The Probability of set A is given as follows.

p(A) = p{N1+ N2 + N3+ ..... + Nn}

p(A) = p(N1) + p(N2) + p(N3) + ..... + p(Nn)

p(A) = (1/N)1 + (1/N)2 + ..... + (1/N)n

p(A) = (n/N)

Let R be an event that, in turn, is a subset of S. The probability of points is given below,

R = {Ni, Nj, Nk}

The probability of each point is 1/N , the probability of R is given below,

p(R) = p{Ni, Nj, Nk}

p(R) = p(Ni) +p(Nj) +p(Nk)

p(R) = 1/N + 1/N + 1/N = 3/N

p(R) = 3/N

Hence, the values are mentioned below,

p(A) = (n/N)

p(R) = 3/N

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Most popular questions from this chapter

A letter is selected at random from the alphabet. What is the probability that it is one of the letters in the word “probability?” What is the probability that it occurs in the first half of the alphabet? What is the probability that it is a letter after x?

(a) Repeat Problem 6 where the “circular” area is now on the curved surface of the earth, say all points at distance s from Chicago (measured along a great circle on the earth’s surface) with sπR3where R = radius of the earth. The seeds could be replaced by, say, radioactive fallout particles (assuming these to be uniformly distributed over the surface of the earth). Find F(s)andf(s) .

(b) Also find F(s)andf(s) ifs1<<R (say s1mile where R=4000miles). Do your answers then reduce to those in Problem 6?

(a) Suppose you have two quarters and a dime in your left pocket and two dimes and three quarters in your right pocket. You select a pocket at random and from it a coin at random. What is the probability that it is a dime? (b) Let x be the amount of money you select. Find E(x).

(c) Suppose you selected a dime in (a). What is the probability that it came from your right pocket?

(d) Suppose you do not replace the dime, but select another coin which is also a dime. What is the probability that this second coin came from your right pocket?

(a) Following the methods of Examples 3,4,5, show that the number of equally likely ways of putting N particles in n boxes,n>N, nNisfor Maxwell Boltzmann particles, C(n,N)for Fermi-Dirac particles, C(n1+N,N)andfor Bose-Einstein particles.

(b) Show that if n is much larger than N (think, for example, ofn=106,N=10), then both the Bose-Einstein and the Fermi-Dirac results in part (a) contain products of N numbers, each number approximately equal to n. Thus show that for n N, both the BE and the FD results are approximately equal tonNN!which is1N!times the MB result.

Set up several non-uniform sample spaces for the problem of three tosses of a coin

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