Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 15: Q16P (page 736)

Suppose you have 3 nickels and 4 dimes in your right pocket and 2 nickels and a quarter in your left pocket. You pick a pocket at random and from it select a coin at random. If it is a nickel, what is the probability that it came from your right pocket?

Short Answer

Expert verified

Answer

The probability of the nickel coming from the right pocket is 923.

Step by step solution

01

Given Information

There are 3 nickels and 4 dimes in the right pocket and 2 nickels and a quarter in the left pocket

02

Definition of Independent Event

The events are said to be independent when the occurrence or non-occurrence of any event does not have any effect on the occurrence or non-occurrence of the other event.

03

Finding the probability that of picking a nickel

Let A be the event that a nickel is picked.

There are total 7 coins in right pocket out of which 3 are nickels and total 3 coins in the left pocket out of which 2 are nickels.

Find the probability of picking a nickel from any pocket.

PA=34+3+22+1=37+23=2321

04

Finding the probability of picking the nickel from right pocket.

Find the probability of picking the nickel from right pocket using the Bayes theorem, PAB=AABPA.

role="math" localid="1654837853424" PAB=372321=923

Thus, the desired probability is 923.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Are the following correct non-uniform sample spaces for a throw of two dice? If

so, find the probabilities of the given sample points. If not show what is wrong.

Suggestion: Copy sample space (2.4) and circle on it the regions corresponding to the points of the proposed non-uniform spaces.

(a) First die shows an even number.

First die shows an odd number.

(b) Sum of two numbers on dice is even.

First die is even and second odd.

First die is odd and second even.

(c) First die shows a number≤3.

At least one die shows a number > 3.

Use Problem 9to find x−in Problem7.

Find the number of ways of putting 2 particles in 5 boxes according to the different kinds of statistics.

Two dice are thrown. Use the sample space (2.4) to answer the following questions.

(a) What is the probability of being able to form a two-digit number greater than

33 with the two numbers on the dice? (Note that the sample point 1, 4 yields

the two-digit number 41 which is greater than 33, etc.)

(b) Repeat part (a) for the probability of being able to form a two-digit number

greater than or equal to 42.

(c) Can you find a two-digit number (or numbers) such that the probability of

being able to form a larger number is the same as the probability of being able

to form a smaller number? [See note part (a)]

A so-called 7-way lamp has three 60-watt bulbs which may be turned on one or two or all three at a time, and a large bulb which may be turned to 100 watts, 200 watts or300 watts. How many different light intensities can the lamp be set to give if the completely off position is not included? (The answer is not 7.)
See all solutions

Recommended explanations on Physics Textbooks

Electromagnetism

Read Explanation

Modern Physics

Read Explanation

Circular Motion and Gravitation

Read Explanation

Geometrical and Physical Optics

Read Explanation

Waves Physics

Read Explanation

Torque and Rotational Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free