Find the number of ways of putting 2 particles in 5 boxes according to the different kinds of statistics.

Short Answer

Expert verified

The solution is derived as mentioned below.

M1=25M2=10M3=15

Step by step solution

01

Given Information.

Number of particles is 2 and number of boxes is 5.

02

Definition of Probability.

Probability means the chances of any event to occur is called it probability.

03

 Step 3: Find the probability

Use Maxwell-Boltzmann: In this model particles are distinguishable so the number of method can be arranged N=2particles in n=5boxes using this method.

M1=nN=52=25

Use Fermi-Dirac: In this model particles are not distinguishable so the number of method can be arranged N=2particles inn=5using this method.

M2=C(n,N)=C(5,2)=10

Use Bose-Einstein: In this model particles are not distinguishable as in Fermi-Dirac but the difference here is that's allowed to put two balls in same box so the number of method can be arrangeddata-custom-editor="chemistry" N=2particles inn=5boxes using this method.

M3=C(n-1+N,N)=C(6,2)=15

Hence, the solution is mentioned below.

M1=25M2=10M3=15

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(a) Following the methods of Examples 3,4,5, show that the number of equally likely ways of putting N particles in n boxes,n>N, nNisfor Maxwell Boltzmann particles, C(n,N)for Fermi-Dirac particles, C(n1+N,N)andfor Bose-Einstein particles.

(b) Show that if n is much larger than N (think, for example, ofn=106,N=10), then both the Bose-Einstein and the Fermi-Dirac results in part (a) contain products of N numbers, each number approximately equal to n. Thus show that for n N, both the BE and the FD results are approximately equal tonNN!which is1N!times the MB result.

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