A weighted coin with probability p of coming down heads is tossed three times; x = number of heads minus number of tails.

Short Answer

Expert verified

The required values are mentioned below.

μ(x)=3[2p1]var(x)=12p12p2σ=23p(1p)

Step by step solution

01

 Step 1: Given Information 

Three coins are tossed.

02

Definition of the cumulative distribution function.

The likelihood that a comparable continuous random variable has a value less than or equal to the function's argument is the value of the function.

03

Find the values.

Let S be the sample space.

S=p3,3p2(1p),3p(1p)2,(1p)3

Find the random variable.

x1=3p1=p3x2=1p2=3p2(1p)

Solve further.

x3=1p3=3p1-p2x4=3p4=1-p3

The mean is given below.

μ(x)=xipi=3p3+3p2(1p)3p31-p2-31-p3=3[p1+3p]=3[2p1]

The variance is given below.

var(x)=Ex2μ2var(x)=9p3+3p21-p+3p1-p2+91-p3-32p-12var(x)=9p3+3p23p3+3p12p+p2+913p+3p2p394p24p+1var(x)=12p12p2

The standard deviation is given below

σ=var(x)σ=12p12p2σ=23p(1p)

The graph is shown below.

Hence, the required values are mentioned below.
μ(x)=3[2p1]var(x)=12p12p2σ=23p(1p)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free