Use the table above and the definitions in Section 17 to find approximate formulas for large x for hn(2)(ix):

Short Answer

Expert verified

The approximate value for large value of x is inx-1ex.

Step by step solution

01

Take out the equations.

The given term is hn(2)(ix).

hn(2)(x)=jn(x)-iyn(x)

As, hn(2)(x)=jn(x)-iyn(x).

Therefore, hn(2)(ix)=jn(ix)-iyn(ix) …… (1)

For larger values of x as follows:

jn(x)=1xsinx-nπ2+Ox-2 …… (2)

yn(x)=-1xcosx-nπ2+Ox-2 …… (3)

02

Use equations (1), (2), and (3) for calculation.

Using equation (1), (2), and (3) as follows:,

hn(2)(ix)=jn(ix)-iyn(ix)=1ixsinix-nπ2-i-1ixcosix-nπ2=1ixsinix-nπ2+i1ixcosix-nπ2=-i2ixsinix-nπ2+1xcosix-nπ2

Simplify further as follows:

hn(2)(ix)=-ixsinix-nπ2+1xcosix-nπ2=1xcosix-nπ2-isinix-nπ2=x-1cosix-nπ2-isinix-nπ2

As,e-iθ=cosθ-isinθ

Therefore, calculate:

hn(2)(ix)=x-1[cosix-nπ2-isinix-nπ2=x-1e-iix-nπ2=x-1e-i2x+inπ2=x-1ex+inπ2=x-1exeinπ2

Simplifying further to get:

hn(2)(ix)=x-1ex(i)n=inx-1ex

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