To sketch the graph of xJ12(x)for x from 0 to π.

Short Answer

Expert verified

The graph of the function xJ12(x)is given below:

Step by step solution

01

 Step 1: Concept of Bessel’s Equation:

The solution of Bessel's equation is,x2y"+xy'+(x2-n2)y=0 .

Jn(x)=k=0(-1)k(k+1)(n+k+1)(x2)2k+n

02

Calculation of the function xJ12(x) for x :

Given function Jp(x)for p=12and x from 0 to π.

role="math" localid="1659269941142" Jp(x)=n=0(-1)n(n+1)(n+1+p)(x2)2n+p

For, p=12in above function.

Jp(x)=n=0(-1)n(n+1)(n+1+p)(x2)2n+pxJ12(x)=n=0-1n(n!)n+12!x22n+12+12(n+1)=n!xJ12(x)=112!x2-132!x23+12!152!x25-13!172!x27+14!192!x2=15!2-1112!x211+16!-1132!x213-17!-1152!x215+......

03

Draw the graph of the function xJ12(x) :

The graph of the function xJ12(x) is given below:

From the above graph, we can observe that there are three zeros of xJ12(x)fromx=0to π.

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